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在AWS Glue中读取镶木地板文件

我是一个AWS胶水新手试图读取我在S3中的一些镶木地板对象,但我失败了ClassNotFoundException.这是我到目前为止基于Glue的最小文档的尝试:

import com.amazonaws.services.glue.GlueContext
import com.amazonaws.services.glue.util.JsonOptions
import org.apache.spark.sql.SparkSession

val gc: GlueContext = new GlueContext(sc)

val spark_session : SparkSession = gc.getSparkSession

val source = gc.getSource("s3", JsonOptions(Map("paths" -> Set("s3://path-to-parquet"))))

val parquetSource = source.withFormat("parquet")

parquetSource.getDynamicFrame().show(1)
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例外情况:

   18/06/11 13:39:11 WARN TaskSetManager: Lost task 0.0 in stage 6.0 (TID 266, ip-172-31-8-179.eu-west-1.compute.internal, executor 16): java.lang.ClassNotFoundException: Failed to load format with name parquet
    at com.amazonaws.services.glue.util.ClassUtils$.loadByFullName(ClassUtils.scala:28)
    at com.amazonaws.services.glue.util.ClassUtils$.getClassByName(ClassUtils.scala:43)
    at com.amazonaws.services.glue.util.ClassUtils$.newInstanceByName(ClassUtils.scala:54)
    at com.amazonaws.services.glue.readers.DynamicRecordStreamReader$.apply(DynamicRecordReader.scala:187)
    ...
Caused by: java.lang.ClassNotFoundException: parquet
    at org.apache.spark.repl.ExecutorClassLoader.findClass(ExecutorClassLoader.scala:82)
    at java.lang.ClassLoader.loadClass(ClassLoader.java:424)
    at java.lang.ClassLoader.loadClass(ClassLoader.java:357)
    at com.amazonaws.services.glue.util.ClassUtils$$anonfun$1.apply(ClassUtils.scala:25)
    at com.amazonaws.services.glue.util.ClassUtils$$anonfun$1.apply(ClassUtils.scala:25)
    at scala.util.Try$.apply(Try.scala:192) …
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amazon-web-services parquet aws-glue

4
推荐指数
1
解决办法
1814
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