小编Tyl*_*aff的帖子

void graph::fillTable()
{
  ifstream fin;
  char X;
  int slot=0;

  fin.open("data.txt");

  while(fin.good()){

  fin>>Gtable[slot].Name;
  fin>>Gtable[slot].Out;
  cout<<Gtable[slot].Name<<endl;
  for(int i=0; i<=Gtable[slot].Out-1;i++)
    {
      **//cant get here**
    fin>>X;
    cout<<X<<endl;
    Gtable[slot].AdjacentOnes.addFront(X);
    }
  slot++;
  }
 fin.close();
}

这是我的代码,基本上它完全符合我的要求但是当文件不再好的时候它会继续阅读.它会输入并输出我正在寻找的所有东西,然后当文件结束时,fin.good()显然不会返回false.这是文本文件.

A 2 B F

B 2 C G

C 1 H

H 2 G I

I 3 A G E

F 2 I E

这是输出

A
B
F
B
C
G
C
H
H
G
I
I
A
G
E
F
I
E

Segmentation fault

-

这是Gtable的类型.

struct Gvertex:public slist …

我只是想跟随android dev上的示例代码来扩展活动中的片段.我有一个更复杂的项目,我正在工作,但我得到的错误与这里的简单错误相同.谁能指出我正确的方向？

扩展片段的类

package com.example.fragtest;


import android.support.v4.app.Fragment;
import android.os.Bundle;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;

public class FragOne extends Fragment {

    @Override
    public void onCreate(Bundle savedInstanceState){
        super.onCreate(savedInstanceState);
    }
    @Override
    public View onCreateView(LayoutInflater inflater,ViewGroup container, Bundle savedInstanceState){
        return inflater.inflate(R.layout.activity_main, container,false);
    }

}

扩展FragmentActivity的类

package com.example.fragtest;

import android.os.Bundle;
import android.view.Menu;
import android.support.v4.app.FragmentActivity;

public class MainActivity extends FragmentActivity {

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
    }

    @Override
    public boolean onCreateOptionsMenu(Menu menu) {
        getMenuInflater().inflate(R.menu.activity_main, menu);
        return true;
    }



}

片段所在的xml

<?xml version="1.0" …

在viewDidLoad()下面,设置我的财产self.textToAnalyze在结果property之中nil在调试器,而直接设置属性使用_textToAnalyze表明,该属性不再为零.为什么是这样？

//
//  TextStatsViewController.m
//  colorSwitcher

#import "TextStatsViewController.h"

@interface TextStatsViewController ()
@property (weak, nonatomic) IBOutlet UILabel *colorfulCharactersLabel;
@property (weak, nonatomic) IBOutlet UILabel *outlinedCharactersLabel;

@end

@implementation TextStatsViewController

-(void)setTextToAnalyze:(NSAttributedString *)textToAnalyze
{

}
-(void)viewDidLoad
{
    _textToAnalyze=[[NSAttributedString alloc] initWithString:@"test" attributes:@{NSForegroundColorAttributeName : [UIColor greenColor],NSStrokeWidthAttributeName :@-3}]; //setting it here with the underscore shows that this property is not nil in the debugger
  //self.textToAnalyze=[[NSAttributedString alloc] initWithString:@"test" attributes:@{NSForegroundColorAttributeName : [UIColor greenColor],NSStrokeWidthAttributeName :@-3}];  //setting it here with the accessor …

我在以下位置找到了我的 JDK /Library/Java/JavaVirtualMachines/jdk1.8.0.jdk

我的 .bash_profile 中有这个

export JAVA_HOME=/Library/Java
export PATH=$JAVA_HOME/bin:$PATH

我已经保存了我的更改 source .bash_profile

现在当我尝试跑步时 sudo apt get install gcc

我收到这个错误

Unable to locate an executable at "/Library/Java/JavaVirtualMachines/jdk1.8.0.jdk/Contents/Home/bin/apt" (-1)

这里发生了什么？

当我运行它时,它将有时打印出一个空终止字符.它大部分时间都会打印,而且可能是打印字符的1/5.

void cryptogram::Encrypt(){

  cout<<"encrypt"<<endl;

char  Alphabet[]="ABCDEFGHIJKLMNOPQRSTUVWXYZ";

  fin.open("original.txt");

  cout<<"file opened";

  if(!fin)

    {
      cout<<"No file exists"<<endl;;
    }else{

  while(fin>>tempS){

        len=tempS.length();
        int a=0;
    for(int j=0;j<len;j++){
          for(a;a<=26;a++){
            tempS[j]=toupper(tempS[j]);
          if(tempS[j]!=Alphabet[a]){//while two characters arent equal
//if the characters arent equal...a is incremented, to see if the character from the word is equal to the next letter in the alphabet

                }else{
                   cout<<Crypto[a]; 
//crypto is an array of char filled with letters that are used to encrypt the message

           if(j!=len){ //if the word still has more characters
               j++;
               a=0; …

我有来自用户的字符串...... 1,2,3具有任意数量的数字.我想要做的是将数字替换为数组中每个数字的indeces处的相应值.所以说我的阵列有[tom] [jerry] [sue].当我正在处理时,我希望我的字符串看起来像汤姆,杰瑞,起诉.我应该使用grep吗？庆典？