我正在使用一个简单的表单,我希望允许用户在表单提交之前确认...我知道使用jQuery会很容易,但我对代码有点困惑...
$(function() {
$(".testform").submit(function() {
$('.submitbtn').text('confirm');
});
});
我知道上面的代码不完整,我希望你的帮助完成它,所以它会发出警告(使用jQuery警报),说"请确认一切是否正确",并将提交按钮上的文字更改为"确认"而不是"提交".如果用户再次点击确认,则会提交表单.我希望这是有道理的.谢谢.
我有以下表的mysql数据库...
| id | amount | tax |
+----+--------+-----+
| 1 | 500 | |
+----+--------+-----+
| 2 | 100 | |
+----+--------+-----+
我必须删除金额列,但在此之前我想将金额行的所有数据从金额行转移到税行.怎么用mysql查询呢？请帮忙.
我在以下jQuery代码中遗漏了什么？
var dob = $('#date').val();
if(dob != ''){
var today = new Date();
var dayDiff = Math.ceil(today - dob) / (1000 * 60 * 60 * 24 * 365);
var age = parseInt(dayDiff);
$('#age').html(age+' years old');
}
我从MySQL db获得了#date的预取值.
<input type="text" value="1988-04-07" id="#date" name="dob" /><p id="age"></p>
它返回NaN,而不是正确的值.
我正在使用Laravel5 Auth系统进行我的新项目,我能够使用注册和登录功能,但没有按预期工作,但是注册不能正常工作,但是我被重定向到指定的url,$redirectAfterLogout但它不会破坏会话,所以即使在点击之后注销按钮我能看到仪表板.
laravel在Auth系统中有一些错误,请建议,谢谢
我有一个包含两个表的数据库 - 公司和报告.我想计算从q1(第1季度)到第2季度(第2季度)的变化.我曾尝试使用(以下)子查询,但主查询失败...
FROM
(SELECT revenue FROM reports WHERE quarter = 'q2' AND fiscal_year = 2018) AS q,
(SELECT revenue FROM reports WHERE quarter = 'q1' AND fiscal_year = 2017) AS lq
这里是DB Fiddle,可以帮助您理解问题和架构:
https://www.db-fiddle.com/f/eE8SNRojn45h7Rc1rPCEVN/4
当前简单查询.
SELECT
c.name, r.quarter, r.fiscal_year, r.revenue, r.taxes, r.employees
FROM
companies c
JOIN
reports r
ON
r.company_id = c.id
WHERE
c.is_marked = 1;
预期结果(这是我需要的):
+---------+----------+----------------+----------+--------------+-----------+------------------+
| Name | Revenue | Revenue_change | Taxes | Taxes_change | Employees | Employees_change |
+---------+----------+----------------+----------+--------------+-----------+------------------+
| ABC …文件没有上传到FTP和错误:警告:ftp_put()[function.ftp-put]:无法打开该文件:没有这样的文件或目录.我们正在使用以下代码:
$server = 'ftp.domain.com';
$ftp_user_name = 'upload@domain.com';
$ftp_user_pass = 'password';
$dest = 'files/test.txt';
$source = 'test.txt';
$src = ini_get("upload_tmp_dir");
$connection = ftp_connect($server);
$login = ftp_login($connection, $ftp_user_name, $ftp_user_pass);
if (!$connection || !$login) { die('Connection attempt failed!'); }
$upload = ftp_put($connection, $dest, $source, FTP_BINARY);
if (!$upload) { echo 'FTP upload failed!'; }
ftp_close($connection);
我试图得到一个循环跟随...
{$product.min_val} //2
{$product.max_val} //8
而我正在努力追随......
{section name=val start=$product.min_val loop=$product.max_val step=0}
<p id="{$smarty.section.val.index}">{$smarty.section.val.index}</p>
{/section}
它打印以下......
<p id="2">2</p>
<p id="3">3</p>
<p id="4">4</p>
<p id="5">5</p>
<p id="6">6</p>
<p id="7">7</p>
您可能已经注意到,它缺少<p id="8">8</p>根据{$product.max_val}
的感谢.
我正在使用线程来检查API网址中的标头状态代码.如果条件为真,我如何打破/停止所有其他线程.请检查以下代码..
import logging, time, threading, requests
#: Log items
logging.basicConfig(format='%(asctime)s %(levelname)s : %(message)s', level=logging.INFO)
class EppThread(threading.Thread):
def __init__(self, group=None, target=None, name=None, args=(), kwargs=None, verbose=None):
threading.Thread.__init__(self, group=group, target=target, name=name, verbose=verbose)
self.args = args
def run(self):
startTime = time.time()
url = self.args[0]
limit = self.args[1]
for i in range(limit):
response = requests.get(url)
if response.status_code != 200:
break
#Exit other similar threads (with same url)
else:
print('Thread {0} - success'.format(thread.getName()))
print('process completed')
# Send Email
number_of_threads = 5
number_of_requests = 100
urls = …请检查我创建的以下类以构建少量XML框架.
class CommandBuilder
{
public function __construct()
{
//
}
public function login($username, $password)
{
$frame = $this->frame();
$command = $frame->addChild('command');
$login = $command->addChild('login');
$login->addChild('username', $username);
$login->addChild('password', $password);
$command->addChild('authKey', 'authkey');
return $frame->asXML();
}
public function info($id)
{
$frame = $this->frame();
$command = $frame->addChild('command');
$login = $command->addChild('product');
$login->addChild('id', $id);
$command->addChild('authKey', 'authkey');
return $frame->asXML();
}
protected function frame()
{
return new SimpleXMLElement(
'<app/>'
);
}
}
什么是避免重复$frame->addChild('command')和$command->addChild('authKey', 'authkey')不改变元素顺序的最佳方法？
请帮助改进代码.谢谢
跟我有点困惑......
消息提醒功能
public static function MsgAlert($email, $name, $subject, $message)
{
$msg = include('mailer.php');
$subject = 'New Message';
if ($email != '' && validate_email($email))
{
$mailer = new PHPMailer();
$mailer->SetFrom(ADMIN_EMAIL, SITE_NAME);
$mailer->AddAddress($email);
$mailer->Subject = $subject;
$mailer->Body = Postman::nl2br($msg);
$mailer->AltBody = $msg;
$mailer->Send();
}
}
我已将我的简报设计放入mailer.php,请检查标记...
mailer.php
<div>
<h1><?php $subject; ?><span>27 September 2011 at 6:26 pm</span></h1>
<div>
<p>Hello <?php $name; ?>,</p>
<?php $message; ?>
</div> <!--message container -->
</div>
我使用正确的方法还是应该做更好的事情,因为它不起作用.请建议.谢谢.