这是我的阵列输出
Array
(
[1] => 1
[2] => 2
[3] =>
)
我怎么知道它[3] =>是空的？
foreach ($array as $key => $value) {
if (empty($value))
echo "$key empty <br/>";
else
echo "$key not empty <br/>";
}
我的出局表明并非空洞.什么是正确的检查方法是空的？
这里有一个例子http://jsfiddle.net/h6PLV/ background:none;
在Google Chrome上,选择选项周围会显示白色.在Firefox中看起来很棒.
如何在Chrome浏览器上删除白色？
我的数组示例
$options = array(
array("brand" => "Puma","code" => "p01","name" => "Puma One"),
array("brand" => "Puma","code" => "p02","name" => "Puma Two"),
array("brand" => "Puma","code" => "p03","name" => "Puma Three"),
array("brand" => "Nike","code" => "n01","name" => "Nike One"),
array("brand" => "Nike","code" => "n02","name" => "Nike Two"),
array("brand" => "Nike","code" => "n03","name" => "Nike Three"),
array("brand" => "Nike","code" => "n04","name" => "Nike Four"),
array("brand" => "Adidas","code" => "a01","name" => "Adidas One"),
array("brand" => "Adidas","code" => "a02","name" => "Adidas Two"),
array("brand" => "Adidas","code" => …这是一个例子我的表格http://jsfiddle.net/GT7fY/
用户在字段上书写时如何将所有文本转换为大写？
这里有一个例子http://jsbin.com/oqisuv/
CSS
body {
background:#e7ebf2 url(http://i.imgur.com/R2VB6.png) center repeat-y;
}
.menu {
width:989px;
margin:auto;
height:100px;
background:#666666;
line-height:100px;
text-align:center;
color:#fff;
}
HTML
<body>
<div class="menu">Hello</div>
</body>
如果您在Google Chrome上查看上面的示例,您会看到.menu看起来像是margin-left:-1px或margin-right:1px.
在Firefox和IE上,它看起来很棒.我该如何解决这个问题？
这里有一个例子http://jsfiddle.net/naqbq/
我怎么抢的当前位置x和y重新定位后的图像？
<input type="hidden" name="source_x" id="source_x" />
<input type="hidden" name="source_y" id="source_y" />
假设我想在/css/文件夹中创建文件调用style.css .
示例:当我单击"保存"按钮时,脚本将创建style.css内容
body {background:#fff;}
a {color:#333; text-decoration:none; }
如果服务器无法写入我想要的文件显示错误消息 Please chmod 777 to /css/ folder
让我知道
我有两个表posts:categories
post_id | post_title | post_content | post_cat
--------------------------------------------------
1 Hello World welcome to my.. 1
. .. .. ..
categories 表
cat_id | cat_name | cat_parent
-----------------------------
1 News NULL
2 Sports 1
. ... ..
让我们说新闻的当前类别链接是 http://domain.com/category/1/
MySQL的声明
SELECT posts.post_id,
posts.post_id,
posts.post_title,
posts.post_content,
posts.post_cat,
categories.cat_id,
categories.cat_name,
categories.cat_parent
FROM posts
INNER JOIN categories
ON posts.post_cat = categories.cat_id
WHERE posts.post_cat = (int)$_GET['cat_id']
所以我们可以得到一个结果 post_cat = 1
根据我目前的数据库结构,我如何删除ID但改变它是一个很棒的slug？示例: -
Main category - http://domain.com/category/news/
Sub category - …$("#label").change(function() {
var src = $(this).data('value');
alert(src);
});
我如何从中获取值data-value？
示例字符串
$string = 'how-do-i-retrieve-last-word'
$string = 'how-do-i-retrieve-last-word-2'
$string = 'how-do-i retrieve-last word-123'
$string = 'how do i retrieve last word test'
我想在上面的字符串中检索最后一个单词,结果应该是:
word
2
123
test
可能重复:
如何在PHP中将逗号分隔的字符串拆分为数组？
使用示例URL格式domain.com/?q[]=a_1&q[]=a_2&q[]=a_3:
在选择选项中,我将selected='selected'使用此代码检索:
<option value="a_1"<?php if(isset($_GET['q'])) if (in_array('a_1', $_GET['q'])) { echo ' selected="selected"'; } ?>>
Sample 1
</option>
<option value="a_2"<?php if(isset($_GET['q'])) if (in_array('a_2', $_GET['q'])) { echo ' selected="selected"'; } ?>>
Sample 2
</option>
<option value="a_3"<?php if(isset($_GET['q'])) if (in_array('a_3', $_GET['q'])) { echo ' selected="selected"'; } ?>>
Sample 3
</option>
如果是URL格式 domain.com/?q=a_1,a_2,a_3,我将如何检索所选值？