小编Naj*_*med的帖子

我一直收到这个错误

无法将视图列"百分比"的数据类型从整数更改为双精度

我有一个函数调用findIntl()它返回一个浮点数

create or replace function findIntl(integer) returns float as $$
  select cast(count(*) as float)
  from students s
  join program_enrolments pe on (s.id = pe.student)
  where s.stype = 'intl' and pe.semester = $1;
$$ language sql;

我在名为findPercent的视图中使用返回的值

create or replace view findPercent(semester, percent) as
  select q6(s.id), findIntl(s.id)
  from semesters s
  where s.id = id and s.term ~ 'S' and s.year >= 2004;

如果我findIntl()用另一列值替换它完全正常,但findIntl()它什么时候会说cannot change data type of view column "percent" from integer …