所以,我正在加入mysql以过滤掉一些不良数据,我遇到了这个奇怪的问题.
payment_transaction_id. 3463. 证明记录在card_transaction_log中:
select count(*)
from card_transaction_log
where payment_transaction_id = 3463;
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证明记录在交易中:
select count(*)
from transaction
where payment_transaction_id = 3463;
>> 1
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但是加入不起作用.
select count(*)
from card_transaction_log a, transaction b
where a.payment_transaction_id = b.payment_transaction_id
and a.payment_transaction_id = 3463;
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老实说,我以前从未在mysql中见过这样的东西.我甚至和我的同事核实过,以确保我不会疯狂和/或愚蠢.
更新:
虽然这与上面相同,但此查询也不起作用:
select count(*)
from card_transaction_log a
join transaction b
on a.payment_transaction_id = b.payment_transaction_id
where a.payment_transaction_id = 3463;
>> 0
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