我读到一个文件太大而无法放入缓冲区时出现致命错误.
FATAL ERROR: v8::Object::SetIndexedPropertiesToExternalArrayData() length exceeds max acceptable value
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要么,
RangeError:在Function.Buffer.allocUnsafe(buffer.js:209:3)中,"size"参数不得大于2147483647
如果我尝试分配1GB缓冲区,我会得到同样的致命错误,
var oneGigInBytes = 1073741824;
var my1GBuffer = new Buffer(oneGigInBytes); //Crash
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Node.js Buffer类实例的最大大小是多少?
有没有办法使用std :: ostream_iterator(或类似的),以便不为最后一个元素放置分隔符?
#include <iterator>
#include <vector>
#include <algorithm>
#include <string>
using namespace std;
int main(int argc, char *argv[]) {
std::vector<int> ints = {10,20,30,40,50,60,70,80,90};
std::copy(ints.begin(),ints.end(),std::ostream_iterator<int>(std::cout, ","));
}
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会打印
10,20,30,40,50,60,70,80,90,
我试图避免落后的分隔符.我想要打印
10,20,30,40,50,60,70,80,90
当然,你可以使用一个循环:
for(auto it = ints.begin(); it != ints.end(); it++){
std::cout << *it;
if((it + 1) != ints.end()){
std::cout << ",";
}
}
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但是考虑到基于C++ 11范围的循环,跟踪位置是很麻烦的.
int count = ints.size();
for(const auto& i : ints){
std::cout << i;
if(--count != 0){
std::cout << ",";
}
}
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我愿意使用Boost.我查看了boost :: algorithm :: …
我一直在切换模板工厂函数来使用(和理解)std :: forward来支持rvalues和移动语义.我通常用于模板类的样板工厂函数始终将参数标记为const:
#include <iostream>
#include <utility>
template<typename T, typename U>
struct MyPair{
MyPair(const T& t, const U& u):t(t),u(u){};
T t;
U u;
};
template<typename T, typename U>
std::ostream& operator<<(std::ostream& os, const MyPair<T,U>& pair){
os << "(" << pair.t << ")=>" << pair.u;
return os;
}
template<typename T, typename U>
MyPair<T,U> MakeMyPair(const T& t, const U& u){
return MyPair<T,U>(t,u);
}
using namespace std;
int main(int argc, char *argv[]) {
auto no_forward = MakeMyPair(num, num);
std::cout << no_forward << std::endl;
auto …Run Code Online (Sandbox Code Playgroud) 我有一个使用Boost ASIO的TCP服务器.我注意到在Linux上使用链接范围的IPv6地址时我无法创建一个boost::asio::ip::tcp::acceptor没有抛出异常.使用全局IPv6地址或IPv4地址将正常工作.
我很确定问题是范围ID未正确设置但我无法弄清楚如何解决问题.
我正在使用ubuntu提供的boost 1.40.0库在Ubuntu 11.04 LTS上进行开发.这是我所拥有的服务器代码的一个非常愚蠢的版本,它显示了这个问题:
#include <boost/asio.hpp>
#include <boost/shared_ptr.hpp>
#include <boost/bind.hpp>
#include <iostream>
#include <string>
/* To Compile:
g++ -Wall -o ./asio-ipv6 ./asio-ipv6.cpp -lboost_system
*/
typedef boost::shared_ptr<boost::asio::ip::tcp::socket> TcpSocketPtr;
typedef boost::shared_ptr<boost::asio::ip::tcp::acceptor> TcpAcceptorPtr;
typedef boost::shared_ptr<boost::asio::ip::tcp::endpoint> TcpEndpointPtr;
class AsioServer{
public:
AsioServer(boost::asio::io_service& io): io_(io){};
//throws
void accept(const std::string& ipString,unsigned short port){
boost::asio::ip::address addr = boost::asio::ip::address::from_string(ipString);
std::cout << "Valid IP address " << ipString << std::endl;
this->endpoint_.reset(new boost::asio::ip::tcp::endpoint(addr,port));
std::cout << "Created endpoint" << std::endl;
//Will throw if a link local IPv6 …Run Code Online (Sandbox Code Playgroud) 我正在尝试使用Python Twisted为简单的TCP服务器编写客户端.当然我对Python很新,刚刚开始关注Twisted,所以我可能做错了.
服务器很简单,你打算使用nc或telnet.没有身份验证.您只需连接并获得一个简单的控制台.我想编写一个添加了一些readline功能的客户端(历史记录和电子邮件,比如ctrl-a/ctrl-e就是我所追求的)
下面是我编写的代码,就像在命令行中使用netcat一样好 nc localhost 4118
from twisted.internet import reactor, protocol, stdio
from twisted.protocols import basic
from sys import stdout
host='localhost'
port=4118
console_delimiter='\n'
class MyConsoleClient(protocol.Protocol):
def dataReceived(self, data):
stdout.write(data)
stdout.flush()
def sendData(self,data):
self.transport.write(data+console_delimiter)
class MyConsoleClientFactory(protocol.ClientFactory):
def startedConnecting(self,connector):
print 'Starting connection to console.'
def buildProtocol(self, addr):
print 'Connected to console!'
self.client = MyConsoleClient()
self.client.name = 'console'
return self.client
def clientConnectionFailed(self, connector, reason):
print 'Connection failed with reason:', reason
class Console(basic.LineReceiver):
factory = None
delimiter = console_delimiter
def __init__(self,factory):
self.factory = …Run Code Online (Sandbox Code Playgroud) 我是Boost Spirit的新手。理想情况下,我想使用Phoenix来确保语法中的两个值相同。我想要工作的简明版本是两个整数相等的元组。
我想解析一个字符串“ 14,14,test”,但由于“ 14,12,test”失败,因为14不等于12。我想打印以下代码:
Good: (14 14 test)
Fail
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目前,由于我允许qi :: int_解析第二个值而没有任何检查,因此两个输入都将通过。
#include <iostream>
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/phoenix.hpp>
#include <boost/fusion/include/vector.hpp>
#include <boost/spirit/include/qi_matches.hpp>
#include <string>
#include <vector>
#include <algorithm>
namespace qi = boost::spirit::qi;
namespace phx = boost::phoenix;
int main(){
std::vector<std::string> test_inputs = {"14,14,test","14,12,test"};
std::for_each(test_inputs.begin(),test_inputs.end(),[](const std::string& input){
boost::fusion::vector<int,int,std::string> result;
int i(0);
auto res = qi::parse(input.begin(),input.end(),
//works but also parses "14,12,test"
qi::int_[phx::ref(i) = qi::_1] >> qi::lit(",") >> qi::int_ >> qi::lit(",") >> +qi::char_,
//Fails to compile
//qi::int_[phx::ref(i) = qi::_1] >> qi::lit(",") >> qi::int_(phx::val(i)) …Run Code Online (Sandbox Code Playgroud)