是什么是backbone-js使用语法的优势/原因
//using a Model instance called model
model.get('attribute')
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并不是
model.attribute
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我刚开始使用骨干,我总是试图直接访问属性
通过角度js 教程,我不明白转发器(功能?)来自茉莉花测试.这是茉莉花还是棱角分明的构造?
页面在<li>元素中确实有一个ng-repeat属性- 但是我没看到它如何转换为测试中对'repeater'的引用
it('should be possible to control phone order via the drop down select box',
function() {
//let's narrow the dataset to make the test assertions shorter
input('query').enter('tablet');
//where does 'repeater' below come from?
expect(repeater('.phones li', 'Phone List').column('phone.name')).
toEqual(["Motorola XOOM\u2122 with Wi-Fi",
"MOTOROLA XOOM\u2122"]);
select('orderProp').option('Alphabetical');
expect(repeater('.phones li', 'Phone List').column('phone.name')).
toEqual(["MOTOROLA XOOM\u2122",
"Motorola XOOM\u2122 with Wi-Fi"]);
});
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我的存储库
package com.gridsearch.repository;
import org.springframework.data.domain.Page;
import org.springframework.data.domain.Pageable;
import org.springframework.data.repository.CrudRepository;
import com.gridsearch.entities.Film;
public interface FilmRepository extends CrudRepository<Film,Short>{
public Page<Film> findAll(Pageable page);
public Film findOne(short Id);
}
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我的服务
package com.gridsearch.service;
import org.springframework.data.domain.Page;
import org.springframework.data.domain.Pageable;
import com.gridsearch.entities.Film;
public interface FilmService {
public Page<Film> allFilms(Pageable page);
public Film findOne(int Id);
}
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我的服务实施
package com.gridsearch.service;
import java.util.ArrayList;
import java.util.List;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.data.domain.Page;
import org.springframework.data.domain.Pageable;
import org.springframework.stereotype.Repository;
import org.springframework.transaction.annotation.Transactional;
import com.gridsearch.entities.Film;
import com.gridsearch.repository.FilmRepository;
@Repository
public class FilmServiceImpl implements FilmService{
@Autowired
private FilmRepository repository;
@Transactional …Run Code Online (Sandbox Code Playgroud) 我需要做一些如下所示的事情; 根据rails中实例对象的值添加jquery效果
("$('#cart').show(2000);") if @cart.total_items ==1
Run Code Online (Sandbox Code Playgroud) 如何配置玻璃鱼以使用应用程序管理的实体管理器?我通过下面给出的配置得到以下错误.
我不希望glassfish管理事务,我只想在持久性单元中使用带有RESOURCE_LOCAL设置的Spring托管事务,而不是JTA
SEVERE: Exception while preparing the app : The persistence-context-ref-name [org.springframework.data.jpa.repository.support.JpaRepositoryFactoryBean/entityManager] .... resolves to a persistence unit called [spring-jpa] which is of type RESOURCE_LOCAL. Only persistence units with transaction type JTA can be used as a container managed entity manager. Please verify your application.
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我的配置:
<persistence version="1.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd">
<persistence-unit name="spring-jpa" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<non-jta-data-source>mysql/mydb</non-jta-data-source>
<properties/>
</persistence-unit>
</persistence>
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我的应用背景:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:jpa="http://www.springframework.org/schema/data/jpa"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.1.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.1.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.1.xsd …Run Code Online (Sandbox Code Playgroud) 我真的不知道下面的属性controlAggregation用于路由SAPUI5应用程序.没有带有该ID的元素.我在这里找到的演示应用程序中找不到任何"页面"的引用: SAPUI5路由演示
"routing": {
"config": {
"routerClass": "sap.m.routing.Router",
"viewType": "XML",
"viewPath": "sap.ui.demo.nav.view",
"controlId": "app",
"controlAggregation": "pages", // what does this do?
"transition": "slide",
"bypassed": {
"target": "notFound"
}
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观点定义如下 - 没有提到'页面'
<mvc:View
controllerName="sap.ui.demo.nav.controller.App"
xmlns="sap.m"
xmlns:mvc="sap.ui.core.mvc"
displayBlock="true">
<App id="app"/>
</mvc:View>
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和
<mvc:View
controllerName="sap.ui.demo.nav.controller.Home"
xmlns="sap.m"
xmlns:mvc="sap.ui.core.mvc">
<Page title="{i18n>homePageTitle}" class="sapUiResponsiveContentPadding">
<content>
<Button id="displayNotFoundBtn" text="{i18n>DisplayNotFound}" press="onDisplayNotFound" class="sapUiTinyMarginEnd"/>
</content>
</Page>
</mvc:View>
Run Code Online (Sandbox Code Playgroud) 它在jqgrid文档中声明下面的代码应允许使用服务器端分页进行本地排序; 网格数据在分页时消失; 之前已经问过这个问题没有明确的答案 - 使用loadonce的建议:true表示分页已关闭 - 我需要分页
稍后编辑完整的html页面和json响应(我现在从php/mysql后端运行).
我的完整HTML页面
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>JQGrid Test</title>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<link rel="stylesheet" type="text/css" href="../dojoproject/jquery-ui-1.8.16.custom/css/start/jquery-ui-1.8.16.custom.css">
<link rel="stylesheet" type="text/css" href="jquery.jqGrid-4.3.1/css/ui.jqgrid.css">
<style type="text/css">
html, body {
margin: 0;
padding: 0;
font-size: 90%;
}
</style>
<script type="text/javascript" src="../dojoproject/jquery-ui-1.8.16.custom/js/jquery-1.6.2.min.js" ></script>
<script type="text/javascript" src="../dojoproject/jquery-ui-1.8.16.custom/js/jquery-ui-1.8.16.custom.min.js" ></script>
<script type="text/javascript" src="jquery.jqGrid-4.3.1/js/i18n/grid.locale-en.js" ></script>
<script type="text/javascript" src="jquery.jqGrid-4.3.1/js/jquery.jqGrid.min.js" ></script>
<script type="text/javascript" src="../dojoproject/jqGrid-4.1.2/js/JSON-js/json2.js" ></script>
<script>
$(function() {
$('#table').jqGrid({
jsonReader : {
repeatitems: false,
cell:"",
id:"0"
},
height:'auto',
url:'/jqgrid/orderdetails.php', …Run Code Online (Sandbox Code Playgroud) 通过默认的'arguments'访问javascript参数并使用诸如'options'之类的显式对象有区别吗?
这两个是否相似,除了那个访问数组参数和另一个访问对象选项?
$.fn.myFn = function(){
if arguments[0]//....
}
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和
$.fn.myFn = function(options){
if options.value //....
}
Run Code Online (Sandbox Code Playgroud) 这些是来自github上的spring amqp示例, 网址 是https://github.com/SpringSource/spring-amqp-samples.git这些类型的java构造函数是什么类型的?他们是吸气者和制定者的简称吗?
public class Quote {
public Quote() {
this(null, null);
}
public Quote(Stock stock, String price) {
this(stock, price, new Date().getTime());
}
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反对这个
public class Bicycle {
public Bicycle(int startCadence, int startSpeed, int startGear) {
gear = startGear;
cadence = startCadence;
speed = startSpeed;
}
Run Code Online (Sandbox Code Playgroud) 我在哪里可以找到使用linq和lambda表达式生成动态sql的好例子?例如,我需要一个方法来获取这些参数
GoupOperator ('And' or 'OR')
A list of objects each with the following parameters:
SearchColumn.
SearchValue.
SearchOperator (equals, contains, does not equal ...)
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以及任何特定列升序或降序排序的另一种方法
如果之前已经正确回答了这个问题,我会很乐意将其删除 - 我以前看到的答案都不够全面,对于一个刚接触linq表达式的人来说,插入现有的应用程序时没什么问题 - 谢谢
下面的测试方法出现在spring-guide 教程中。是否有一个不太复杂的语法来编写这个测试,或者我怎样才能把它分解成更小的块?
verify(orderService).createOrder(
org.mockito.Matchers.<CreateOrderEvent>argThat(
allOf( org.hamcrest.Matchers.<CreateOrderEvent>
hasProperty("details",
hasProperty("dateTimeOfSubmission", notNullValue())),
org.hamcrest.Matchers.<CreateOrderEvent>hasProperty("details",
hasProperty("name", equalTo(CUSTOMER_NAME))),
org.hamcrest.Matchers.<CreateOrderEvent>hasProperty("details",
hasProperty("address1", equalTo(ADDRESS1))),
org.hamcrest.Matchers.<CreateOrderEvent>hasProperty("details",
hasProperty("postcode", equalTo(POST_CODE)))
)));
Run Code Online (Sandbox Code Playgroud) 试图复制msdn引用在这里不起作用,并给出一个错误,我想增加json序列化的允许长度
<configuration>
<configSections>
<sectionGroup name="system.web.extensions" type="System.Web.Configuration.SystemWebExtensionsSectionGroup, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35">
<sectionGroup name="scripting" type="System.Web.Configuration.ScriptingSectionGroup, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35">
<section name="scriptResourceHandler" type="System.Web.Configuration.ScriptingScriptResourceHandlerSection, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35" requirePermission="false" allowDefinition="MachineToApplication"/>
<sectionGroup name="webServices" type="System.Web.Configuration.ScriptingWebServicesSectionGroup, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35">
<section name="jsonSerialization" type="System.Web.Configuration.ScriptingJsonSerializationSection, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35" requirePermission="false" allowDefinition="Everywhere" />
<section name="profileService" type="System.Web.Configuration.ScriptingProfileServiceSection, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35" requirePermission="false" allowDefinition="MachineToApplication"/>
<section name="authenticationService" type="System.Web.Configuration.ScriptingAuthenticationServiceSection, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35" requirePermission="false" allowDefinition="MachineToApplication" />
<section name="roleService" type="System.Web.Configuration.ScriptingRoleServiceSection, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35" requirePermission="false" allowDefinition="MachineToApplication" />
</sectionGroup>
</sectionGroup>
</sectionGroup>
</configSections>
...
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