小编Nif*_*Ojo的帖子

任务:
编写一个程序,检查作为参数提供的单词是否是等值线.Isogram是一个不会出现多次字母的单词.

创建一个名为is_isogram的方法,它接受一个参数,一个单词来测试它是否是等值线图.此方法应返回单词的元组和布尔值,指示它是否是等值线图.

如果提供的参数是空字符串,则返回参数和False :(参数,False).如果提供的参数不是字符串,则引发TypeError,并显示消息'Argument should a a string'.

例:

is_isogram("abolishment")

预期结果:

("abolishment", True)

可见测试

from unittest import TestCase

class IsogramTestCases(TestCase):
  def test_checks_for_isograms(self):
    word = 'abolishment'
    self.assertEqual(
      is_isogram(word),
      (word, True),
      msg="Isogram word, '{}' not detected correctly".format(word)
    )

  def test_returns_false_for_nonisograms(self):
    word = 'alphabet'
    self.assertEqual(
      is_isogram(word),
      (word, False),
      msg="Non isogram word, '{}' falsely detected".format(word)
    )

  def test_it_only_accepts_strings(self):
    with self.assertRaises(TypeError) as context:
      is_isogram(2)
      self.assertEqual(
        'Argument should be a string',
        context.exception.message,
        'String inputs allowed only'
      )

我的解决方案

def is_isogram(word):
    if type(word) != str: …