小编7l-*_*l04的帖子

我正在尝试创建一个表(一个9乘11的数组),它存储一个函数通过几个排序函数所花费的时间.

我想我希望这个表是一个字符串.我目前无法解决如何转换chrono到string并且无法在线查找任何资源.

我是否需要放弃表格的字符串输入,或者有没有办法将这些时间差异存储在字符串中？

for (int i = 0; i<8;i++) // sort 8 different arrays
{ 
    start = chrono::system_clock::now(); 
    //Sort Array Here
    end = chrono::system_clock::now();
    chrono::duration<double> elapsed_seconds = end-start;
    table[1][i] = string(elapsed_seconds)   // error: no matching conversion for functional style cast
}

我正在尝试使用 Python 3 在 pipelinev 中安装库请求。我尝试过：

1. pip install requests，然后忘记pip仅安装 Python 2，导致，
2. pip3 install requests，肯定会返回

Requirement already satisfied: requests in /Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/site-packages (2.19.1)
Requirement already satisfied: idna<2.8,>=2.5 in /Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/site-packages (from requests) (2.7)
Requirement already satisfied: urllib3<1.24,>=1.21.1 in /Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/site-packages (from requests) (1.23)
Requirement already satisfied: certifi>=2017.4.17 in /Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/site-packages (from requests) (2018.8.24)
Requirement already satisfied: chardet<3.1.0,>=3.0.2 in /Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/site-packages (from requests) (3.0.4)

当我使用 运行 python 文件时import requests，一切正常，但是当我运行时pipenv run python mypythonscript.py，出现错误ModuleNotFoundError: No module named 'requests'。请告诉我缺少什么。

I\xe2\x80\x99m 收到错误 I\xe2\x80\x99m 不确定如何处理，与 I\xe2\x80\x99m 尝试的元组分配相关。下面的函数incr出现left-hand of expression not valid错误。我有什么误解吗？

struct Fib {\n    i: u64,\n    fa: u64,\n    fb: u64,\n}\n\nimpl Fib {\n    fn incr(&mut self) {\n        self.i += 1;\n        (self.fa, self.fb) = (self.fa + self.fb, self.fa);\n    }\n}\n