我一直在尝试找出如何将纹理发送到着色器,但是我无法弄清楚。我的代码对我来说不错,但我的第二个纹理是黑色。
void setShaders() {
glEnable (GL_TEXTURE_2D);
v2 = glCreateShader(GL_VERTEX_SHADER);
f2 = glCreateShader(GL_FRAGMENT_SHADER);
load_shader(v2,"a.vert");
load_shader(f2,"a.frag");
glCompileShader(v2);
glCompileShader(f2);
p = glCreateProgram();
glAttachShader(p,v2);
glAttachShader(p,f2);
GLubyte* textura=LoadImageToTexture("d.jpg");
GLubyte* textura2=LoadImageToTexture("n.jpg");
GLuint texturaID[2];
glGenTextures(2, texturaID);
glBindTexture(GL_TEXTURE_2D, texturaID[0]);
glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_MIN_FILTER, GL_NEAREST);
glTexImage2D(GL_TEXTURE_2D,0,GL_RGBA, w, h, 0, GL_RGBA,GL_UNSIGNED_BYTE,(GLvoid*)textura );
glBindTexture(GL_TEXTURE_2D, texturaID[1]);
glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_MIN_FILTER, GL_NEAREST);
glTexImage2D(GL_TEXTURE_2D,1,GL_RGBA, w, h, 0, GL_RGBA,GL_UNSIGNED_BYTE,(GLvoid*)textura2 );
glLinkProgram(p);
glUseProgram(p);
GLint baseImageLoc = glGetUniformLocation(p, "tex");
GLint normImage = glGetUniformLocation(p, "norm");
glUniform1i(baseImageLoc, 0);
glUniform1i(normImage, 1);
glActiveTexture(GL_TEXTURE0 + 0);
glBindTexture(GL_TEXTURE_2D, texturaID[0]);
glActiveTexture(GL_TEXTURE0 + 1);
glBindTexture(GL_TEXTURE_2D, texturaID[1]);
}
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着色器[顶点]
void …Run Code Online (Sandbox Code Playgroud) 我使用 MySQL 员工的测试数据库 - 测试数据库 我想优化查询
SELECT emp_no, SUM(salary)
FROM salaries
WHERE from_date < '1999-01-01'
group by emp_no;
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查询费用:287790
哪些索引可以帮助我?
我尝试使用emp_noandsalary和emp_noand创建索引from_date,但没有结果。有一个完整的扫描索引。
也尝试使用OVER(PARTITION BY)代替GROUP BY
SELECT emp_no, SUM(salary) OVER (PARTITION by emp_no)
FROM salaries
WHERE from_date < '1999-01-01';
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OVER例如,避免完整索引扫描或使用GROUP BY
oracle apex 中的v()和nv()函数有什么区别?
我遇到了这个nv()函数,我唯一能让谷歌吐槽的就是这个nvl()函数。
apex_custom_auth.post_login(
p_uname => l_authenticated_username,
p_session_id => nv('APP_SESSION'),
p_app_page =>
apex_application.g_flow_id||':'||nvl(apex_application.g_flow_step_id,0));
Run Code Online (Sandbox Code Playgroud) 我学到的第一门语言是PHP,但最近我学习了Python.由于这些都是"高级"语言,我发现它们有点难以接受.我也试过学习Objective-C,但我放弃了.
那么,我应该学习什么语言来桥接Python到C.
I'm trying to connect to CosmosDB through my SpringBoot app. I have all of this working if I run the app with Spring or via Intellij. But, when I run the app in Docker I get the following error message:
com.azure.data.cosmos.CosmosClientException: The authorization token is not valid at the current time.
Please create another token and retry
(token start time: Thu, 26 Mar 2020 04:32:10 GMT,
token expiry time: Thu, 26 Mar 2020 04:47:10 GMT, current server time: Tue, …Run Code Online (Sandbox Code Playgroud) 我无法理解这个问题,我不确定我做错了什么。
我想等待 Flux 结束然后Mono返回serverResponse
我已附上代码片段,它将doOnNext填充categoryIdToPrintRepository.
我已经查看了如何在通量结束后返回单声道,并发现了“then”,但在处理 onNextSite 之前仍然执行“then”方法,这会导致错误:
java.lang.IllegalArgumentException: 'producer' type is unknown to ReactiveAdapterRegistry
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我究竟做错了什么?
public Mono<ServerResponse> retrieveCatalog(ServerRequest ignored) {
return Mono.just("start").flatMap(id ->
Flux.fromIterable(appSettings.getSites())
.subscribeOn(ForkJoinPoolScheduler.create("SiteCatalogScheduler"))
.doOnNext(this::onNextSite)
.then(Mono.from(ServerResponse.ok().body(categoryIdToPrintRepository.getSortedTreeValues(), String.class))));
}
private void onNextSite(Integer siteId) {
IntStream.range(1, appSettings.getCatalogMaxValue()).parallel().forEach(catalogId -> {
Optional<SiteCatalogCategoryDTO> cacheData =
siteCatalogCacheUseCaseService.getSiteCatalogResponseFromCache(siteId, catalogId);
cacheData.ifPresentOrElse(siteCatalogCategoryDTO -> {/*do nothing already exist in cache*/},
() -> {
Mono<SiteCatalogCategoryDTO> catalogCategoryDTOMono = WebClient.create(getUri(siteId, catalogId))
.get().retrieve().bodyToMono(SiteCatalogCategoryDTO.class);
catalogCategoryDTOMono.subscribe(siteCatalogCategoryDTO ->
handleSiteServerResponse(siteCatalogCategoryDTO, siteId, catalogId));
});
});
}
private void handleSiteServerResponse(SiteCatalogCategoryDTO siteCatalogCategoryDTO, …Run Code Online (Sandbox Code Playgroud) 更新我的堆栈后运行 cdk deploy:
export function createTaskXXXX (stackScope: Construct, workflowContext: WorkflowContext) {
const lambdaXXXX = new lambda.Function(stackScope, 'XXXXFunction', {
runtime: Globals.LAMBDA_RUNTIME,
memorySize: Globals.LAMBDA_MEMORY_MAX,
code: lambda.Code.fromAsset(CDK_MODULE_ASSETS_PATH),
handler: 'xxxx-handler.handler',
timeout: Duration.minutes(Globals.LAMBDA_DURATION_2MIN),
environment: {
YYYY_ENV: (workflowContext.production) ? 'prod' : 'test',
YYYY_A_LOCATION: `s3://${workflowContext.S3ImportDataBucket}/adata-workflow/split-input/`,
YYYY_B_LOCATION: `s3://${workflowContext.S3ImportDataBucket}/bdata-workflow/split-input/` <--- added
}
})
lambdaXXXX.addToRolePolicy(new iam.PolicyStatement({
effect: Effect.ALLOW,
actions: ['s3:PutObject'],
resources: [
`arn:aws:s3:::${workflowContext.S3ImportDataBucket}/adata-workflow/split-input/*`,
`arn:aws:s3:::${workflowContext.S3ImportDataBucket}/bdata-workflow/split-input/*` <---- added
]
}))
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我意识到这些更改不会在 stack.template.json 中更新:
...
"Runtime": "nodejs12.x",
"Environment": {
"Variables": {
"YYYY_ENV": "test",
"YYYY_A_LOCATION": "s3://.../adata-workflow/split-input/"
}
},
"MemorySize": 3008,
"Timeout": 120
}
... …Run Code Online (Sandbox Code Playgroud) 我正在尝试使用 Spotify API 添加Track到用户的库,但收到 400 响应状态。我已经尝试过这个请求,并且由于标头令牌而Alamofire开始出现错误。postCountSpotify
这是代码的一部分:
func spotify_addToLibrary()
{
self.spotify_verifySession(completion:{ success , auth in
if !success
{
return
}
let postString = "ids=[\"\(self.trackid)\"]"
let url: NSURL = NSURL(string: "https://api.spotify.com/v1/me/tracks")!
var request = URLRequest(url: url as URL)
request.cachePolicy = .useProtocolCachePolicy
request.timeoutInterval = 8000
request.addValue("application/x-www-form-urlencoded;charset=UTF-8", forHTTPHeaderField: "Content-Type")
request.addValue("application/json", forHTTPHeaderField: "Accept")
request.addValue("Bearer \(auth.session.accessToken!)", forHTTPHeaderField: "Authorization")
request.httpMethod = "post"
request.httpBody = postString.data(using: .utf8)
URLSession.shared.dataTask(with: request) {data, response, err in
if err == nil
{
print("Add to Library …Run Code Online (Sandbox Code Playgroud) 我在玩反应堆
public @NotNull Mono<ServerResponse> findXXXXSse(final ServerRequest request) {
return request.bodyToMono(XXXXSearch.class)
.doOnNext(this::validate)
.flatMap(this::findXXXXSse)
.switchIfEmpty(this.emptyBodyException());
}
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我想知道使用.doOnNext(this::validate)是否正确。从我的角度来看,我不确定在findXXXXSse?之前调用 validate 。
我错了吗?
我有一个类,constructor它将对象的地址作为参数.
MyClass(OtherClass * otherClass);
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在Destructor这个类中,我尝试delete了实例OtherClass.
~MyClass() {
if(otherClass != nullptr) {
delete otherClass;
}
}
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我遇到的问题是,当我调用constructor它时,我用一个元素来stack代替heap它来调用它,因此我将其称为如下:
MyClass myClass(&otherObject);
所以当myClass对象超出范围时,我得到一个例外.如果我的OtherObject变量是stack在heap?或者?上声明的,我怎么能够喜欢?或者换句话说,我怎么知道我是否可以delete对象?