我得到一个说"必须实现OnFragmentInteractionListener,我已经拥有它...
我看过这里提出的每一个问题,没有人帮助过我.
有人可以帮帮我吗?
错误:
FATAL EXCEPTION: main
Process: com.example.android.navigationdrawer, PID: 5916
java.lang.RuntimeException: com.example.android.navigationdrawer.MainActivity@3aefae64 must implement OnFragmentInteractionListener
at com.example.android.navigationdrawer.FragmentCamera.onAttach(FragmentCamera.java:83)
at android.support.v4.app.FragmentManagerImpl.moveToState(FragmentManager.java:1019)
at android.support.v4.app.FragmentManagerImpl.moveToState(FragmentManager.java:1248)
at android.support.v4.app.BackStackRecord.run(BackStackRecord.java:738)
at android.support.v4.app.FragmentManagerImpl.execPendingActions(FragmentManager.java:1613)
at android.support.v4.app.FragmentManagerImpl$1.run(FragmentManager.java:517)
at android.os.Handler.handleCallback(Handler.java:739)
at android.os.Handler.dispatchMessage(Handler.java:95)
at android.os.Looper.loop(Looper.java:135)
at android.app.ActivityThread.main(ActivityThread.java:5930)
at java.lang.reflect.Method.invoke(Native Method)
at java.lang.reflect.Method.invoke(Method.java:372)
at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1405)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1200)
Run Code Online (Sandbox Code Playgroud)
主要活动(扩展到OnFragmentInteractionListener)
package com.example.android.navigationdrawer;
import android.content.Intent;
import android.net.Uri;
import android.os.Bundle;
import android.support.design.widget.FloatingActionButton;
import android.support.design.widget.NavigationView;
import android.support.design.widget.Snackbar;
import android.support.v4.app.Fragment;
import android.support.v4.view.GravityCompat;
import android.support.v4.widget.DrawerLayout;
import android.support.v7.app.ActionBarDrawerToggle;
import android.support.v7.app.AppCompatActivity;
import android.support.v7.widget.Toolbar;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.ImageView; …Run Code Online (Sandbox Code Playgroud) 我正在使用PHP和MySQL(PHPMyAdmin)创建一个注册表单,当我在浏览器(Mozilla Firefox)上打开页面时,我得到了
解析错误:语法错误,第71行意外的$ end
<?php
require('config.php');
if(isset($_POST['submit'])){
//Verificació
$email1 = $_POST['email1'];
$email2 = $_POST['email2'];
$pass1 = $_POST['pass1'];
$pass2 = $_POST['pass2'];
if($email1 == $email2){
if ($pass1 == $pass2){
//Tot bé!
$name = mysql_escape_string($_POST['name']);
$lname = mysql_escape_string($_POST['lname']);
$email1 = mysql_escape_string($email1);
$email2 = mysql_escape_string($email2);
$pass1 = mysql_escape_string($pass1);
$pass2 = mysql_escape_string($pass2);
}else{
die("Sorry, your passwords didn't match");
}
}else{
die("Sorry, your emails didn't match");
}
}else{
echo <<<EOD
<form action='register.php' method='POST'>
First name:<input type='text' name='name' /><br/>
Last name:<input type='text' name='lName' /><br/>
Username:<input type='text' name='username' …Run Code Online (Sandbox Code Playgroud)