小编Tha*_*yen的帖子

在for循环中添加值

int n, total, array[4] = {5,4,2,7}

for (n =0; n<4; n++)
{
total = array[n] + array[n+1];
}
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5 + 4 = 9 + 2 = 11 + 7 = 18

我知道我需要将sum的值存储到变量中,但是如何使变量循环返回到数组中的下一个数字.

c for-loop

0
推荐指数
1
解决办法
6230
查看次数

C中的错误malloc

我不确定这是错误的它说不兼容隐式内置func我确实包括string.h文件但它仍然给我一个错误

 int name_read;
 int name_bytes = 100;
 char *name;

 printf("Please enter name:\n");
 name = (char *)malloc(name_bytes + 1);
 name_read = getline(&name, &name_bytes, stdin);
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c malloc

0
推荐指数
1
解决办法
659
查看次数

多次调用后,从C调用汇编代码擦除地址

部件

TITLE   adding numbers
.486
.MODEL      FLAT,C
option      casemap:none
include     C:\Users\Thao\Hello\msvcrt.inc
.data
formating  DB "%s",10,0
           DB 0
num1       DB "0000000000"
           DB 0

num2       DB "0000000000"
           DB 0

AC_balance DB "0000000000"
           DB 0


.code

adding      PROC C, number1:DWORD , number2:DWORD

            mov esi, number1
            lea edi, num1 
            mov ecx, SIZEOF num2
            rep movsb 
            mov     eax, offset num1

            push    eax

            mov     eax, OFFSET formating
            push    eax
            call    printf
            pop     eax
            pop     eax
;---------------------------------------------------            

            mov esi, number2
            lea edi, num2 
            mov ecx, SIZEOF num2 …
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c assembly

0
推荐指数
1
解决办法
135
查看次数

jquery语法提交表单

<html>
    <head>
        <script type="text/javascript" src="http://www.superpseudostocks.com/SPS/js/jquery-1.8.2.min.js"></script>
        <script type="text/javascript">
            $("#form").submit(function () {
                alert("click");
            });
        </script>
    </head>
    <body>
        <div style="width:517px; margin-top:20px;height:260px;">
            <form id="form" action="javascript:void(0);" method="POST">
                <fieldset style="height:200px;" id="Withdraw">
                    <legend><b><font size="4" color=black>Deposit</font></b>
                    </legend> <font color="black" size=4>Deposit funds into system balance from registered bank account</font>
                    <br>
                    <br>
                    <div style="width:480px; height:20px; margin: auto;" id="ErrorBox"></div>
                    <br> <span class="tab2"></span>
                    <label for='amount'><font color="black"><b>Please enter an amount to withdraw from bank account</b></font> </label>
                    <br> <span class="tab3"></span>$
                    <input type='text' name='Amount' id='Amount' maxlength="50" size="40" />
                    <br>
                    <br>
                    <input style="width:100px; height:40px;" type='SUBMIT' name='Confirm' …
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javascript jquery

0
推荐指数
1
解决办法
264
查看次数

java mysql编写的声明

我正在尝试使用java进行数据库的简单插入,并告诉我我的sql语法已关闭.但是当我复制我打印出的字符串并将其放入phpmyadmin中的sql命令时,它正确地执行命令,我似乎无法弄清楚我在java中的字符串查询是否有错.

java.sql.PreparedStatement statement;

String physicanInsertQuery = "INSERT INTO physician_phi VALUES(?,?,?,?,?,?,?,?)";
statement = ddp.getConnect().prepareStatement(physicanInsertQuery);

statement.setString(1, "id");
statement.setString(2, "first");
statement.setString(3, "last");
statement.setString(4, "middle");
statement.setString(5, "male");
statement.setString(6, "8179999999");
statement.setString(7, "test@gmail.com");
statement.setString(8, "1991-5-15");
System.out.println(statement.toString());
statement.executeUpdate(physicanInsertQuery);
statement.close();
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这是在执行之前打印出来的查询.

INSERT INTO physician_phi VALUES('FML123','FirstName','LastName','MiddleName','Male','8179999999','john@server.department.company.com','1991-2-7')
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这是它在控制台中显示的错误

com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '?,?,?,?,?,?,?,?)' at line 1
    at sun.reflect.GeneratedConstructorAccessor26.newInstance(Unknown Source)
    at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source)
    at java.lang.reflect.Constructor.newInstance(Unknown Source)
    at com.mysql.jdbc.Util.handleNewInstance(Util.java:411)
    at …
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java mysql sql

0
推荐指数
1
解决办法
352
查看次数

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c ×3

assembly ×1

for-loop ×1

java ×1

javascript ×1

jquery ×1

malloc ×1

mysql ×1

sql ×1