我将Springboot版本更新到2.7.0，返回错误后：
\n描述：
\nAn attempt was made to call a method that does not exist. The attempt was made from the following location:\n\n org.webjars.WebJarAssetLocator.scanForWebJars(WebJarAssetLocator.java:183)\n\nThe following method did not exist:\n\n \'io.github.classgraph.ClassGraph io.github.classgraph.ClassGraph.acceptPaths(java.lang.String[])\'\n\nThe calling method\'s class, org.webjars.WebJarAssetLocator, was loaded from the following location:\n\n jar:file:/home/gabriel/.m2/repository/org/webjars/webjars-locator-core/0.50/webjars-locator-core-0.50.jar!/org/webjars/WebJarAssetLocator.class\n\nThe called method\'s class, io.github.classgraph.ClassGraph, is available from the following locations:\n\n jar:file:/home/gabriel/.m2/repository/io/github/classgraph/classgraph/4.8.69/classgraph-4.8.69.jar!/io/github/classgraph/ClassGraph.class\n\nThe called method\'s class hierarchy was loaded from the following locations:\n\n io.github.classgraph.ClassGraph: file:/home/gabriel/.m2/repository/io/github/classgraph/classgraph/4.8.69/classgraph-4.8.69.jar\n\n\nAction:\n\nCorrect the classpath of your application so that it contains compatible versions of the classes …我正在构建一个Metro App.
在MainPage.xaml.cs中,我实例化Album,如下所示:
Album album = new Album(2012); //With the album ID as its parameter.
ListView1.ItemsSource = album.Songs;
在Album.cs中,构造函数如下:
public Album(int ID)
{
this.ID = ID;
Initialize(); //Serves as a wrapper because I have to call httpClient.GetStreamAsync() and "async" doesn't work for the constructor.
}
最后,Initialize方法:
private async void Initialize()
{
//...some code...
HttpClient cli = new HttpClient();
Stream SourceStream = await HttpClient.GetStreamAsync("http://contoso.com");
//...some code...
this.Songs = Parse(SourceStream);
}
问题是当它运行到GetStreamAsync时,它会ListView1.ItemsSource = album.Songs直接转到album.Songs null.
有这个问题的快速解决方案吗？Thx提前.
我正在尝试为每个构建变体重命名我的APK文件,以包含应用程序名称,versionName,versionCode和内部版本号.到目前为止,除了应用程序名称之外,我的所有工
我想使用AndroidManifest.xml文件用于android:label 的相同值.这来自字符串资源@string/app_name.我已经看到了使用以下方法替换资源值的能力:
resValue "string", "app_name", "Some new value"
但我只想读取此值并使用它来命名我的APK文件.
android.applicationVariants.all { variant ->
variant.outputs.each { output ->
renameApk(variant, output)
}
}
def renameApk(variant, output) {
def apkPath = output.outputFile.parent
def baseName = project.archivesBaseName
baseName += "-${variant.buildType.name}"
// add version name and version code
baseName += "-v${variant.mergedFlavor.versionName}-${variant.mergedFlavor.versionCode}"
// if built on jenkins ci, add jenkins build number:
def buildNumber = System.getenv('BUILD_NUMBER')
if (buildNumber && buildNumber.size() > 0) {
baseName += "-b${buildNumber}"
}
// if the variant …我是MVVM的新手,我坚持使用数据绑定.我的视图页面上有一个按钮,可以动态创建文本框,但是我无法看到如何将这些文本框绑定到ViewModel中的List.
在我看来,我有:
<Button x:Name="btWebsite" Grid.ColumnSpan="2" Width="50" Height="50" Click="btWebsite_Click" Margin="23,245,259,202">
<StackPanel x:Name="pnWebsiteButton" Orientation="Horizontal">
<Image x:Name="imgWebsite" Source= "Images/webIcon.jpg" Stretch="Fill" HorizontalAlignment="Left" VerticalAlignment="Top"/>
</StackPanel>
</Button>
<GroupBox x:Name="grpWebsite" VerticalAlignment="Top" HorizontalAlignment="Left" Margin="73,245,0,0" Grid.ColumnSpan="2" Height="51" Width="170" BorderBrush="{x:Null}" BorderThickness="0">
<ScrollViewer x:Name="pnScrollWebsite" VerticalScrollBarVisibility="Auto" HorizontalScrollBarVisibility="Disabled" Margin="0,0,0,-6">
<StackPanel x:Name="pnWebsite" Orientation="Vertical" Grid.ColumnSpan="2" HorizontalAlignment="Left" Margin="1,2,0,0" VerticalAlignment="Top" IsEnabled="True">
</StackPanel>
</ScrollViewer>
</GroupBox>
按钮后面的代码是:
private void btWebsite_Click(object sender, RoutedEventArgs e)
{
var newTextBox = new TextBox();
newTextBox.Text = "type the website address...";
newTextBox.Foreground = Brushes.Gray;
newTextBox.Width = 150;
newTextBox.Name = "txtWebsite" + iWebsites;
pnWebsite.Children.Add(newTextBox);
pnWebsite.RegisterName(newTextBox.Name, newTextBox); …首先,他们原谅我的英语,因为它不是我的母语.我有一个接收通用列表的方法List<T>.我想要的是通过整个列表进行操作并能够更新一个名为Eliminated of each class的列T,它是布尔类型的,是否可以这样做？有谁能够帮我.
这是我到目前为止:
// Delete (Change status delete = true)
public void Delete<T>(List<T> data)
{
if (data != null)
{
data.ForEach(x =>
{
...
});
}
}
提前致谢!
我有一个应用程序,我用RecycleView用CardViews.该CardView含有EditText当我添加一个新的,现在CardView到RecycleView了EditText应该有重点,键盘应该会出现.
我怎样才能做到这一点？我试图在以下内容中添加一些代码onBindViewHolder:
public void onBindViewHolder(TodoViewHolder holder, final int position) {
...
if(holder.tvDescription.requestFocus()) {
window.setSoftInputMode(WindowManager.LayoutParams.SOFT_INPUT_STATE_ALWAYS_VISIBLE);
}
...
}
或者虽然创造ViewHolder但它没有奏效.
public class TodoViewHolder extends RecyclerView.ViewHolder {
protected CheckBox cbDone;
protected EditText tvDescription;
protected FloatingActionButton btnDelete;
public TodoViewHolder(View itemView) {
super(itemView);
cbDone = (CheckBox)itemView.findViewById(R.id.cbDone);
tvDescription = (EditText) itemView.findViewById(R.id.tvDescription);
btnDelete = (FloatingActionButton) itemView.findViewById(R.id.btnDelete);
if(tvDescription.requestFocus()) {
window.setSoftInputMode(WindowManager.LayoutParams.SOFT_INPUT_STATE_ALWAYS_VISIBLE);
}
}
}
这是我AdapterCode的解决方案:
public abstract class ArrayAdapter<T, …Java 7
List<Person> personList = Person.createShortList();
// Sort with Inner Class
Collections.sort(personList, new Comparator<Person>() {
public int compare(Person p1, Person p2) {
return p1.getSurName().compareTo(p2.getSurName());
}
});
Java 8
Collections.sort(personList, (Person p1, Person p2) ->
p1.getSurName().compareTo(p2.getSurName()));
for (Person p : personList) {
p.printName();
}
如果接口Comparator有2个方法而不只是一个compare可以使用Lambda？
例如
public interface Comparator<T> {
int compare(T o1, T o2);
int compareTest(T o1, T o2);
}