背景
Javascripts和Styles文件目前我处理这种情况如下:
BundleConfig文件
//Styles for LTR
bundles.Add(new StyleBundle("~/Content/bootstarp").Include(
"~/Content/bootstrap.css",
"~/Content/CustomStyles.css"));
// Styles for RTL
bundles.Add(new StyleBundle("~/Content/bootstrapRTL").Include(
"~/Content/bootstrap-rtl.css",
"~/Content/CustomStyles.css"));
//Scripts for LTR
bundles.Add(new ScriptBundle("~/scripts/bootstrap").Include(
"~/Scripts/bootstrap.js",
"~/Scripts/CmsCommon.js"
));
//Scripts for RTL
bundles.Add(new ScriptBundle("~/scripts/bootstrapRTL").Include(
"~/Scripts/bootstrap-rtl.js",
"~/Scripts/CmsCommon.js"
));
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在意见中实施:
@if (this.Culture == "he-IL")
{
@Styles.Render("~/Content/bootstrapRTL")
}
else
{
@Styles.Render("~/Content/bootstrap")
}
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问题:
我想知道是否有更好的方法来实现它,我希望:
处理检测哪种文化并在捆绑中拉出正确文件的逻辑(代码隐藏)不在视图中.
所以在视图中我所要做的就是调用一个文件.
如果我在视图中保留逻辑,则意味着我将不得不在每个视图中处理它.我想避免它.
我正在尝试使用LINQ创建一个group by语句.我收到错误当前上下文中不存在名称'con'.
在select之后的代码中,我试图获取ActivityID值,但列表'con'不可用.
List<Contribution> contributions =
contLogic.GetAllContibutionsByActivityIDToList(ActivityID);
var groups = from con in contributions
group con by con.Response
into gResponse
select new
{
grop = gResponse.Count(),
con.ActivityID
};
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我看过微软的样本,我不知道我做错了什么.
微软示例:
List<Product> products = GetProductList();
var orderGroups = from prod in products
group prod by prod.Category into prodGroup
select new { Category = prodGroup.Key, Products = prodGroup };
ObjectDumper.Write(orderGroups, 1);
Run Code Online (Sandbox Code Playgroud) 我需要更新存在特定值的行.该ExecuteNonQuery返回0这意味着数据库未更新.在调试中单步执行时,将触发更新并包含正确的值,但不会进行任何更新.
string verifySql = @"UPDATE UserInfo SET Verified='@Verified'
WHERE UserID='@UserID'";
using (var con = newSqlConnection(
ConfigurationManager.ConnectionStrings["UserInfoDB"].ConnectionString))
using (var cmd = new SqlCommand(verifySql, con))
{
con.Open();
cmd.Parameters.AddWithValue("@Verified", "Verified " + DateTime.Now);
cmd.Parameters.AddWithValue("@UserID", user.UserId);
Response.Write(cmd.ExecuteNonQuery());
con.Close();
}
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