我已经得到回应,但我不需要这样
{
"status": "200",
"id": 1,
"email": "a@a.a",
"mobile": "",
"source": "",
"source_id": "",
"message": "Bad Request : Already Logged In"
}
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我需要在另一个对象中返回这些数据,例如:
{
{
"status": "200",
}
{
"id": 1,
"email": "a@a.a",
"mobile": "",
"source": "",
"source_id": "",
"message": "Bad Request : Already Logged In"
}
}
Run Code Online (Sandbox Code Playgroud)