我在 Vue 组件脚本部分定义了一个接口,当我尝试将其导入另一个打字稿文件时,会出现此错误:
TS2614: Module '"../pages/categories/alimentation/index.vue"' has no exported member 'BenefitDetails'. Did you mean to use 'import BenefitDetails from "../pages/categories/alimentation/index.vue"' instead
<script lang="ts">
import { Component, Vue } from 'vue-property-decorator'
export interface BenefitDetails {
name: string
frequency: string
cost: number
icon: string
description: string
}
@Component
export default class MyComponent extends Vue {
// my props ...
mounted() {}
}
</script>
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// Error in import below
import { BenefitDetails } from '~/pages/categories/alimentation/index.vue'
export function getBenefitFrequencyColor({ frequency }: BenefitDetails) {
switch …Run Code Online (Sandbox Code Playgroud) 做这个练习https://github.com/rust-lang/rustlings/blob/main/exercises/option/option3.rs我发现了这个ref关键字,我很困惑何时应该在模式匹配中使用&or 。ref在这个例子中,每场比赛都输出相同的消息,但我无法说出它们的区别:
struct Point { x: i32, y: i32}
fn main() {
let y: Option<Point> = Some(Point { x: 100, y: 200 });
match &y {
Some(p) => println!("Co-ordinates are {},{} ", p.x, p.y),
_ => println!("no match"),
}
match y {
Some(ref p) => println!("Co-ordinates are {},{} ", p.x, p.y),
_ => println!("no match"),
}
match &y {
Some(ref p) => println!("Co-ordinates are {},{} ", p.x, p.y),
_ => println!("no match"), …Run Code Online (Sandbox Code Playgroud) 我需要构建一个在Kubernetes集群中加入许多裸机节点的应用程序,我需要在这些节点之间使用共享的持久文件系统.节点应该能够同时在该文件系统中进行读写.
额外奖励:即使群集崩溃,有没有办法让文件系统保持活动状态?
我读过这篇文章,但无法找到这个问题的答案.
这个问题对我来说非常重要,因为这是我本科毕业论文的要求.
我有一个Recipe代表此 YAML 块的类:
id: Ex1
uses:
- Database: ["D1", "D2"]
- MetaFeature: ["M1", "M2"]
- Algorithm: ["A1", "A2"]
- Config: ["C1", "C4"]
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id: Ex1
uses:
- Database: ["D1", "D2"]
- MetaFeature: ["M1", "M2"]
- Algorithm: ["A1", "A2"]
- Config: ["C1", "C4"]
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有没有办法将此 YAML 解析为 Recipe 类,而无需创建其他类或执行一些技巧?
我有一个抽象类,Task有两个方法execute(),并finish()为如下:
abstract class Task {
abstract void execute();
private void finish() {
// Do something...
}
}
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如何确保隐式调用的execute()子类中的重载方法作为最后一条语句?Task finish()
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