小编Tro*_*ing的帖子

我有一个列表，我将其转换为 FormArray 以生成 html 中的按钮列表。我想按名称过滤汽车

汽车组件.html

  <input #searchBox id="search-box" (input)="search(searchBox.value)" />

<form [formGroup]="form" *ngIf="showCars">
              <input type="button" class ="btn"  formArrayName="carsList" *ngFor="let car of carsList$ | async; let i = index" value="{{carsList[i].name}}" >
        </form>

CarComponent.ts

 carsList$: Observable<Car[]>;
  private searchTerms = new Subject<string>();
  search(term: string): void {
    this.searchTerms.next(term);
  }

constructor(private formBuilder:FormBuilder,...)
{
  this.form = this.formBuilder.group({
      carsList: new FormArray([])
    });

this.addButtons();

}

 ngOnInit() {
    this.spinner.show(); 
    this.carsList$ = this.searchTerms.pipe(
      debounceTime(300),
      distinctUntilChanged(),
      switchMap((term:string)=> 
      this.carsList ??? // Is this correct ?? What do I put here ? …

对于我可以使用ajax/jquery和存储过程快速完成的问题,我一直在摸不着头脑.我想要

1)使用Entity Framework和视图模型从数据库表中获取的值填充下拉列表.我不想使用VIEWBAG或VIEWDATA.任何帮助赞赏.

2)如何使用具有所有默认字段的视图模型生成创建视图？脚手架适用于模型,但不适用于视图模型？

我的模特

public class Employee
{
    public int EmployeeID { get; set; }
    public string Name { get; set; }
    public string Gender { get; set; }
    public string City { get; set; }
    public string Level { get; set; }
    public int DepartmentId { get; set; }
}

public class Grade
{
    public int ID { get; set; }
    public string Level { get; set; }
}

查看模型

public class GradeSelectListViewModel
{

    public Employee Employee { …

我是C#的新手,我有一个要解决的递归问题.我希望在这个硬币更换问题中获得最少数量的硬币.我已经为它调整了一个算法,但我需要返回一个类型为Change的对象,它将包含最小可能的组合.

我试图实现一个算法,但我有所有可能的组合.

using System;
using System.Collections.Generic;
using System.Linq;

// Do not modify change
class Change
{
    public long coin2 = 0;
    public long bill5 = 0;
    public long bill10 = 0;
}

class Solution
{

    // Do not modify method signature
    public static Change OptimalChange(long s)
    {
        Change _change = new Change();
        //To implement here
        return _change;
    }

    public static int GetCombinations(int total, int index, int[] list, List<int> cur)
    {
        if (total == 0)
        {
            foreach (var i in cur) …

我刚刚在控制器中添加了另一个 post 方法，Swagger Swashbuckle 崩溃了。如何解决这个问题？

 [HttpPost]
        public IActionResult CreateCars(List<Car> cars)
        {
            _carService.CreateCars(cars);
            return NoContent();
        }

System.NotSupportedException: HTTP method "POST" & path "api/Cars" overloaded by actions - IrkcnuApi.Controllers.CarsController.Create (WebApi),MyWebAPI.Controllers.CarsController.CreateCars (MyWebApi). Actions require unique method/path combination for OpenAPI 3.0. Use ConflictingActionsResolver as a workaround
   at Swashbuckle.AspNetCore.SwaggerGen.SwaggerGenerator.GenerateOperations(IEnumerable`1 apiDescriptions, SchemaRepository schemaRepository)
   at Swashbuckle.AspNetCore.SwaggerGen.SwaggerGenerator.GeneratePaths(IEnumerable`1 apiDescriptions, SchemaRepository schemaRepository)
   at Swashbuckle.AspNetCore.SwaggerGen.SwaggerGenerator.GetSwagger(String documentName, String host, String basePath)
   at Swashbuckle.AspNetCore.Swagger.SwaggerMiddleware.Invoke(HttpContext httpContext, ISwaggerProvider swaggerProvider)
   at Microsoft.AspNetCore.Diagnostics.DeveloperExceptionPageMiddleware.Invoke(HttpContext context)