小编Hey*_*eyi的帖子

请在下图中找到代码.1.将函数的返回值(实际上抛出一个错误)分配给使用关键字"let"声明的变量'withLet'.2.调用'withLet',发生错误:'withLet未定义'.3.尝试使用'let'断言'withLet',错误显示已经声明'withLet'.

但是'var'不存在悖论(请参见下图).

我很好奇是什么导致了这两种情况之间的不同行为.它是非常有线的,"未定义","已经声明"描述了一个相同的变量.

let withLet = (function() {throw 'error!'})()
var withVar = (function() {throw 'error!'})()
//VM2470:1 Uncaught error!
//(anonymous) @ VM2470:1
//(anonymous) @ VM2470:1
withLet
//VM2484:1 Uncaught ReferenceError: withLet is not defined at 
//<anonymous>:1:1
//(anonymous) @ VM2484:1
withVar
//undefined
let withLet = 'sth'
//VM2520:1 Uncaught SyntaxError: Identifier 'withLet' has already been 
//declared
//at <anonymous>:1:1
//(anonymous) @ VM2520:1
withVar = 'sth'
//"sth"

截图: