小编Wim*_*oen的帖子

我想用Curl发送复杂的Post数据.

我尝试发送的数据:

Array
(
    [test] => Array
        (
            [0] => 1
            [1] => 2
            [2] => 3
        )

    [file] => CURLFile Object
        (
            [name] => H:\wwwroot\curl/upload.txt
            [mime] => 
            [postname] => 
        )

)

我需要使用post-side中的变量作为$ _POST ["test"]和$ _FILES ["file"]但我无法实现.对于(有时是多维的)数组数据,我需要http_build_query但是会破坏文件.如果我不使用http_build_query,我的数组会给出"数组到字符串转换"错误.

我怎样才能使这个工作？码:

的index.php

$curl = curl_init();

$postValues = Array("test" => Array(1,2,3));
$postValues["file"] = new CurlFile(dirname(__FILE__). "/upload.txt");

curl_setopt($curl, CURLOPT_URL, "localhost/curl/post.php");
curl_setopt($curl, CURLOPT_POST, true);
curl_setopt($curl, CURLOPT_POSTFIELDS, $postValues);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, TRUE);

$curlResult = curl_exec($curl);
$curlStatus = curl_getinfo($curl);

echo $curlResult;

post.php中

print_r($_REQUEST);
print_r($_FILES);

我想为 Chrome 编写一个扩展程序来观看我的 XHR 调用，我发现我必须为此使用 webRequest。

我想获得请求的响应正文，但我永远找不到如何做到这一点。这可能吗？

// chrome.browserAction.onClicked.addListener(function (tab) {
    var callback = function(details) {
        var url = details.url;

        console.log(details);
    };

    var filter = {
        urls: ["*://safan.dev/*"]
    };

    var ops = ["requestBody"];

    chrome.webRequest.onBeforeRequest.addListener(
        callback, filter, ops
    );
// });

并体现：

{
  "manifest_version": 2,

  "name": "Forge of Empires",
  "description": "FOE",
  "version": "1.0",

  "browser_action": {
    "default_icon": "icon.png"
  },
  "permissions": [
    "webRequest",
    "<all_urls>"
  ],
  "background": {
    "scripts": ["logic.js"]
  }
}