这是一段UI代码
<select id="order_unit_line_rate_806782_is_addenda_enabled" class="selects_for_487886" onchange="select_addendum(806782, this);dateShowMemory(this.options[this.selectedIndex].value, '806782');" uniqueattr="Dynamic Site Accelerator / Dynamic Site Accelerator / Additional Usage Commitment / drop down" name="order_unit_line_rate[806782][is_addenda_enabled]">
<option value="0" uniqueattr="Dynamic Site Accelerator / Dynamic Site Accelerator / Additional Usage Commitment / Fee"> Fee </option>
<option value="1" uniqueattr="Dynamic Site Accelerator / Dynamic Site Accelerator / Additional Usage Commitment / See Attached Addendum"> See Attached Addendum </option>
</select>
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当<option>
标签被嵌套在里面<select>
的标签.我需要click()
在第二个<option>
元素上,它是下拉列表中的一个项目.当我尝试使用id/uniqueattr click()
在<select>
标签上时,可以点击下拉列表.
如何遍历<option>
嵌套在下面的标签<select>
并单击右侧的项目?