我无法从angularjs中的php数组中获取interview_docs数据.我尝试了很多json编码选项,但它没有问过.如何在js中获取interview_docs数据这是我的数组:
Array(
[id] => 1
[tag] => 2
[title] => Test
[job_submission_id] => 0
[job_id] => 14
[candidate_id] => 55
[mail_to] => test@gmail.com
[cc_to] => test@gmail.com
[interviewer] => test@gmail.com
[interview_type] => 1
[interview_date] => 2017-10-04
[from_time] => 00:00:00
[to_time] => 01:00:00
[to_date] =>
[location] =>
[time_zone] => Asia/Kolkata
[status] => 1
[comments] => dwedfwef
[created_by] => 1
[modified_by] => 1
[created_at] => 2017-10-03 12:21:13
[updated_at] => 2017-10-03 12:21:13
[job_title] => Test
[candidate_name] => New t
[candidates] => Array
(
[id] …我一直在使用 Laravel 中的默认身份验证功能..我在一个刀片文件中发现 Auth::user()->name 能够显示存储在用户表中的名称..但我想知道它是如何显示的刀锋中的名字，带有雄辩的呼唤。