小编Dot*_*per的帖子

我有一个与网站分开的类库项目.当我构建单独的类库并移动ddl网站bin目录但它不移动*pdb文件.

类库中的Post-Build事件命令Line选项

我用

copy /y "$(TargetPath)" "E:\inetpub\Site\bin\"  

复制DLL,但它不会移动debug*pdb文件,我想移动这两个文件.我怎样才能做到这一点？是否可以使用宏构建器.如果是的话,有人可以告诉我这些步骤吗？

string inputString = "1/10 EP Sp'arrowha?wk XT R;TR 2.4GHz Red";
//Characters Collection: (';', '\', '/', ':', '*', '?', ' " ', '<', '>', '|', '&', ''')
string outputString = "1 10 EP Sp arrowha wk XT R TR 2.4GHz Red";

我有一列ntext数据类型和非XML.它存储所有xml数据.我需要更新记录中的xml节点.它抛出一个错误,说"错误使用xml数据类型方法'修改'.在此上下文中应该使用非mutator方法."

begin transaction
declare @Cps_Id int;
set @Cps_Id = 236;
declare @Cps_Message nvarchar(1024);
set @Cps_Message = 'updating cpsia message with smoking'; 

update table_name
set column_name =  CONVERT(xml,column_name).modify('replace value of (/root/ProductInformation/CPSIA/CpsiaDetails/Item[CpsiaId=sql:variable("@Cps_Id")]/CpsiaMessage/text())[1] with sql:variable("@Cps_Message")') 
WHERE Convert(xml,column_name).exist('/root/ProductInformation/CPSIA/CpsiaDetails/Item[CpsiaId=sql:variable("@Cps_Id")]')=1 

rollback  

示例XML:

<root>
  <ProductInformation>
    <Name> Truck with Battery Charger</Name>
    <Description>Fr.</Description>
    <CPSIA>
      <CpsiaDetails>
        <Item>
          <CpsiaId>456</CpsiaId>
          <CpsiaMessage>waring</CpsiaMessage>
        </Item>
        <Item>
          <CpsiaId>236</CpsiaId>
          <CpsiaMessage>to health</CpsiaMessage>
        </Item>
      </CpsiaDetails>
    </CPSIA>
  </ProductInformation>
</root>

我有一列ntext数据类型和非XML.它存储所有xml数据.我需要根据xml节点值获取记录.=>输入值是CpsiaId = 456并且应该返回在xml中具有此值的所有记录

我试过了 select * from tableName where convert(xml,column_name).value('data((/root/ProductInformation/CPSIA/CpsiaDetails/Item/CpsiaId)[1])','int') = 456

但它没有工作....任何想法或其他方式获取基于xml节点值的记录.

示例Xml:

<root>
  <ProductInformation>
    <Name> Truck with Battery Charger</Name>
    <Description>Fr.</Description>
    <CPSIA>
      <CpsiaDetails>
        <Item>
          <CpsiaId>456</CpsiaId>
          <CpsiaMessage>waring</CpsiaMessage>
        </Item>
        <Item>
          <CpsiaId>236</CpsiaId>
          <CpsiaMessage>to health</CpsiaMessage>
        </Item>
      </CpsiaDetails>
    </CPSIA>
  </ProductInformation>
</root>

DateTime input = DateTime.Now; //06/02/2011 04:05:07 PM
expectedOutput string = "20110602040507";

我希望根据此(年,月,日,小时,分钟,秒)模式之后的日期获得上述输出字符串.

我想从NTEXT列获取一个xml节点值,其中包含基于where子句查询另一个xml节点值的xml. RDBMS类型:Microsoft SQL Server T-SQL 这里:我想根据StoreId where子句值获取Code节点值.我怎么得到它？输入:100输出:ABCDE

例如:

<root>
  <StoreProfile>
    <General>
     <StoreId>100</StoreId>
     <Code>ABCDE</Code>
    </General>
  </StoreProfile>
</root>

string inputString = "Flat---Head-----Self-Tap-Scr---ews----3-x-10mm-8pc";
string outputString = "Flat-Head-Self-Tap-Scr-ews-3-x-10mm-8pc";