小编Sai*_*toD的帖子

grad = (1/m * (h-y)' * X) + lambda * [0;theta(2:end)]'/m; 
cost =  1/(m) * sum(-y .* log(h) - (1-y) .* log(1-h)) + lambda/m/2*sum(theta(2:end).^2); 

如何将这两行更改为python？我试图用zip'和'做同样的工作.但它显示错误.