假设响应和协变量数据如下：
(1.4, 0.0), (1.4, -2.0), (0.8, 0.0), (0.4,2.0).
我想(1, -1/8)通过将惩罚参数应用于斜率来找到脊参数 k，为此脊估计是。
我尝试解决绕过验证码的问题，但不起作用。
import requests
import bs4
from twocaptcha import TwoCaptcha
import os
TwoCaptcha_api_key = ""
renew_url = ""
renew_session = requests.session()
renew_request = renew_session.get(renew_url)
renew_content = renew_request._content
renew_soup = bs4.BeautifulSoup(renew_content, 'lxml')
renew_sitekey = renew_soup.find('div', {"class":"g-recaptcha"})['data-sitekey']
renew_token = renew_soup.find('input', {"name":"_token"})['value']
solve = TwoCaptcha(TwoCaptcha_api_key)
result = solve.recaptcha(
sitekey=renew_sitekey,
url=renew_url)
recaptcha_response = result['code']
postdata = {"username": "AAAAAAA", "g-recaptcha-response": f"{recaptcha_response}", "_token": f"{renew_token}" }
renew_post = renew_session.post(renew_url, data=postdata)
print(renew_post)
我收到了这个错误
Traceback (most recent call last):<br>
File "", line 18, in <module><br>
result = solve.recaptcha(<br>
AttributeError: 'TwoCaptcha' …我有一个长度很多的虚拟文本。
Sample_text = """Nunc tempus metus sem, at posuere nulla volutpat viverra.Sed nec nisl imperdiet, egestas ex et, sodales libero.Suspendisse egestas id dui at aliquet.Nulla a justo neque.Pellentesque non urna iaculis, maximus dolor at, pellentesque eros. Duis mi velit, ornare eu mollis sed, congue eget nisl. Ut suscipit, elit eu mattis vehicula, justo quam vulputate urna, nec tempor augue ligula sed nisl. Phasellus vel augue eu nibh sodales pretium ornare vel felis.Vivamus vitae suscipit orci ."""
我正在寻找一种方法来证明文本的合理性，例如right对齐方式。浏览了文本换 …