为了做出以下类型的断言
create assertion assert
check "EMPTY SET" = (select User
from Video
where date=current_date()
group by user
having count(*) >= 10
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这个说法是对的吗?
create assertion assert
check 0 = (select count(*)
from Video
where date=current_date()
group by user
having count(*) >= 10
Run Code Online (Sandbox Code Playgroud) 请看一下这两段伪汇编代码:
1)
li $t0,53
sll $t1,$t0,2
srl $t2,$t0,2
sra $t3,$t0,2
print $t1
print $t2
print $t3
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2)
li $t0,-53
sll $t1,$t0,2
srl $t2,$t0,2
sra $t3,$t0,2
print $t1
print $t2
print $t3
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在第一种情况下,输出为:
212
13
13
后者是:
-212
107374...
-14
但不应该:sra (-53) = - (srl 53) ?
Wikipidea说,Perl有一个显性实现,可用作其规范的参考,而C语言则由标准ANSI ISO指定.
我学会了C语言而没有阅读单行标准,这是正常的吗?
我想知道标准(即自然语言文档)如何能够描述编程语言而不涉及任何主导实现.
language-agnostic programming-languages language-specifications
以下函数必须将一条线分成2行或更多行,每行比s短.
char **splitline(FILE *fp, int s)
{
char **l;
char c;
int ccounter;
int lcounter;
c = fgetc(fp);
if (c == EOF)
{
return NULL;
}
lcounter=0;
l = malloc(sizeof(char **));
l[lcounter] = malloc((SIZE+2)*sizeof(char));
ccounter = 0;
while (c != EOF && c != '\n')
{
l[lcounter][ccounter] = c;
ccounter++;
c = fgetc(fp);
if (ccounter == SIZE)
{
l[lcounter][ccounter] = '\n';
ccounter++;
l[lcounter][ccounter] = '\0';
realloc(l, (lcounter+2) * sizeof(char **));
lcounter++;
l[lcounter] = malloc((SIZE+2) * sizeof(char));
ccounter = 0;
} …
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