小编Jay*_*ena的帖子

我们可以使用视图来提高查询的性能吗？

我通过MVC3创建一个项目,并首先使用EFCode进行DataAccess Layer.

在我的DataBase中我有PackaginInfo表,在项目中我关心Package Class,这是我的代码:

public class Package
{
    public decimal PackageID { get; set; }
    public decimal Title { get; set; }
    public decimal Cost { get; set; }
    public bool isFree { get; set; }

}


public class ParandShopsEntities : DbContext
{       

    protected override void OnModelCreating(System.Data.Entity.ModelConfiguration.ModelBuilder modelBuilder)
    {
        modelBuilder.Entity<Package>().MapSingleType().ToTable("PackagingInfo"); 

    }

    public DbSet<Package> PackagingInfo { get; set; }
}

当我调试我的项目时,我得到错误:错误System.Data.Entity.ModelConfiguration.EntityTypeConfiguration'不包含'MapSingleType'的定义,也没有扩展方法'MapSingleType'接受类型'System.Data.Entity.ModelConfiguration的第一个参数可以找到.EntityTypeConfiguration'(你是否缺少using指令或程序集引用？)E:\ Projects\ein co\89-11-23\Parand\MvcApplication1\Models\ParandShopsEntities.cs

请.帮我

当我们使用实体框架作为数据层时，我们能否获得SQL Server 2010表分区的好处？该表每天将有 10,000 条记录，并将按创建日期进行分区（例如：- 超过 30 天的记录和新的记录）

我在使用我创建的ListView时遇到问题:我想在单击它时选择一个项目.

我的代码如下:

protected void onResume() {
...
ListView lv = getListView(); 
lv.setOnItemSelectedListener(new OnItemSelectedListener() 
{
    public void onItemSelected(AdapterView<?> adapterView, View view, int pos, long id) {
        Log.v(TAG, "onItemSelected(..., " + pos + ",...) => selected: " + getSelectedItemPosition());
    }
    public void onNothingSelected(AdapterView<?> adapterView) {
        Log.v(TAG, "onNothingSelected(...) => selected: " + getSelectedItemPosition());
    }
});
lv.setOnItemClickListener(new OnItemClickListener()
{
    public void onItemClick(AdapterView<?> adapterView, View view, int pos, long id) {
        lv.setSelection(pos);               
        Log.v(TAG, "onItemClick(..., " + pos + ",...) => selected: " + getSelectedItemPosition());              
    } …

我正在学习单页应用程序并在阅读文档本身之后

我想知道单页应用程序模式只是使用外部模板剔除的 Web 应用程序中的一页（例如：html 页面）？

我的意思是（我正在使用 MVC ）：

-mywebsite
 + some js files
 + some css files
 + index.html
 + controllers
 + models

我希望有人可以为我解释更多有关此模式的信息。谢谢。

我需要在网格行和详细信息视图上绑定一些事件.我正在使用一个可观察的视图模型,其中注册了一些事件,并尝试使用行模板和详细信息模板将它们绑定到DOM.到目前为止没有进展.

$("#grid").kendoGrid({
    sortable:true,
    rowTemplate:'<tr class="k-master-row"> 
         <td class="k-hierarchy-cell"><a class="k-icon k-plus" href=""></a></td>
        <td><a data-bind:"click:highlight">click in row ${id}</a></td><td>${bool}</td>
    </tr>',
    detailTemplate:'<a data-bind:"click:highlight">click In details ${id}</a>',
    columns: [{field:'id',sortable:false}, {field:'bool'}],
    dataBound: function(e) {
      var grid=$("#grid").data('kendoGrid');
      grid.expandRow("tr.k-master-row");
    }
});


var model=( {
    highlight:function(){
       console.log(this.id);
    },
   items:[{id: 1123, bool: true}, {id: 223, bool: false}]
});
kendo.bind($("#grid"),kendo.observable(model));

这是jsFiddle http://jsfiddle.net/amGmr/9/ .是否有可能使用MVVM绑定事件与网格？

我有这样的Odata结果

        {"odata.metadata":"https://localhost/DocTalkMobileWebApiOData/odata/$metadata#MasterPatient/@Element","PatUniqueId":"39e713db-6a0e-4e59-bf7b-033f4fc47ad5",  "PatID":null,
"pat_lname":"White","pat_fname":"Peter","pat_mi":"     ","pat_ssn":"270787655","pat_dob":"08/07/1973","pat_sex":"M","pat_status":null,"priInsID":2,"secInsID":1,"PCPID":1,"InternalDrID":1,"EXPID":1,"EXPDate":"","pat_phone":null,"isNew":true,"imported":true,"byWhom":"dt","lastUpdate":"2011-03-30T09:41:57.36","changeStamp":"AAAAAAAAIUE=","address":"","city":"","state":"","zip":"","currentMcp":"","currentVisitCount":-2,"otherId":"543674","pcpName":null,"hasChanges":true,"ProgramSource":null,"mrnID":"","createdBy":null,"createdDate":"2007-10-26T10:16:15","expLocation":null,"ethnicId":1,"prefLanguageId":1,"raceId":1
    }

我试图通过kendo.ui.datasource得到这个结果:

 newPatient = new kendo.data.DataSource({
        type: 'odata', // <-- Include OData style params on query string.
        transport: {
            read: {
                url: url + '/MasterPatient(guid\'00000000-0000-0000-0000-000000000000\')', // <-- Get data from here
                dataType: "json" // <-- The default was "jsonp"
            },

            parameterMap: function (options, type) {
                var paramMap = kendo.data.transports.odata.parameterMap(options);

                delete paramMap.$inlinecount; // <-- remove inlinecount parameter.
                delete paramMap.$format; // <-- remove format parameter.

                return paramMap;
            }
        },
        schema: {
            data: function (data) {                 
                return data; …

我有代码第一个实现流动的层次结构,

 BaseContact{
   Public int Id{get;set;}
   public string Name{get;set;} 
//..
 }

 Person:BaseContact{

   public string Designation{get;set;} 
//..
 }
Company:BaseContact{
     public int NumOfEmployees{get;set;} 
//..
 }

我想通过仅使用Id值来识别人或公司？目前我正在使用反思来确定它是个人还是公司.有没有其他方法来识别它而不做太多？