小编Ale*_*ici的帖子

jquery/javascript如果jpg不匹配则删除div

我有这个HTML代码:

<div class="first div">
    <div class="second">  
        <div class="title">Hi</div>
        <div class="test-icon" style="background-image: url(https://1.jpg);"></div>
    </div>
</div>
<div class="first div">
    <div class="second">  
        <div class="title">Hi</div>
        <div class="test-icon" style="background-image: url(https://12.jpg);"></div>
    </div>
</div>
<div class="first div">
    <div class="second">  
        <div class="title">Hi</div>
        <div class="test-icon" style="background-image: url(https://123.jpg);"></div>
    </div>
</div>
<div class="first div">
    <div class="second">  
        <div class="title">Hi</div>
        <div class="test-icon" style="background-image: url(https://good.jpg);"></div>
    </div>
</div>
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如果背景图像不是,则可以删除所有带"first div"类的元素:url(https://good.jpg);?所以最终的回应是:

<div class="first div">
    <div class="second">  
        <div class="title">Hi</div>
        <div class="test-icon" style="background-image: url(https://good.jpg);"></div>
    </div>
</div>
Run Code Online (Sandbox Code Playgroud)

我将不胜感激,谢谢!

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