小编Fad*_*dov的帖子

我用 Python 编写了代码来计算 10000 以下的友好数字的总和：

def amicable(a, b):
   total = 0
   result = 0
   for i in range(1, a):
      if a % i == 0:
        total += i
   for j in range(1, b):
      if b % j == 0:
        result += j
   if total == b and result == a:
        return True
   return False

sum_of_amicables = 0
for m in range (1, 10001):
    for n in range (1, 10001):
        if amicable(m, n) == True and m != n:
            sum_of_amicables = …

x = [0, 1, -2, 3, 4, 5]
all ([i for i in range (1, len(x)) if x [i-1] < x[i]]) ?

为什么要打印此代码True？
1> -2所以它应该打印False我认为.