小编Adr*_*rna的帖子

如何从uib-datepicker编辑datepicker/day.html

在文档中uib-datepicker有一个名为的选项template-url

<-- https://angular-ui.github.io/bootstrap/#/datepicker -->
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这是内容:

<div ng-switch="datepickerMode" role="application" ng-keydown="keydown($event)">
<uib-daypicker ng-switch-when="day" tabindex="0"></uib-daypicker>
<uib-monthpicker ng-switch-when="month" tabindex="0"></uib-monthpicker>
<uib-yearpicker ng-switch-when="year" tabindex="0"></uib-yearpicker>
</div>
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但我需要修改"uib-daypicker"中的模板; 我尝试复制模板,datepicker/day.html但它不起作用,因为它是一个指令...所以,我该怎么办?

datepicker angularjs angular-ui-bootstrap

2
推荐指数
1
解决办法
3336
查看次数

Reportlab 中的段落隐藏溢出

我有一个Table有 2 个单元格的单元,每个单元格内部都有一个Paragraph

from reportlab.platypus import Paragraph, Table, TableStyle
from reportlab.lib.styles import ParagraphStyle
from reportlab.lib.units import cm

table_style_footer = TableStyle(
            [
                ('LEFTPADDING', (0, 0), (-1, -1), 0),
                ('RIGHTPADDING', (0, 0), (-1, -1), 0),
                ('TOPPADDING', (0, 0), (-1, -1), 0),
                ('BOTTOMPADDING', (0, 0), (-1, -1), 0),
                ('BOX', (0, 0), (-1, -1), 1, (0, 0, 0)),
                ('VALIGN', (0, 0), (-1, -1), 'TOP'),
            ]
        )

style_p_footer = ParagraphStyle('Normal')
style_p_footer.fontName = 'Arial'
style_p_footer.fontSize = 8
style_p_footer.leading = 10

Table([
       [
        Paragraph('Send …
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python reportlab platypus python-3.x

2
推荐指数
1
解决办法
1706
查看次数

*在python上是什么意思?

我有下一个查询.

item = [item.export_simple()
            for item in session.query(Item)
                               .filter(and_(
                                       Item.companyId == company_id,
                                       or_(
                                           True if search == "" else None,
                                           or_(*[Item.name.like('%{0}%'.format(s)) for s in words]),
                                           or_(*[Item.code.like('%{0}%'.format(s)) for s in words])
                                            ))).order_by(Item.name)]
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还有这个.

if type == "code":
            src = [Item.code.like('%{0}%'.format(s)) for s in words]
        elif type == "name":
            src = [Item.name.like('%{0}%'.format(s)) for s in words]

 session.query(Item)
                    .filter(and_(
                        Item.companyId == company_id,
                        Item.typeItem == item_type,
                        or_(
                            True if search == "" else None,
                            or_(*src)
                        )))
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在这两种情况下,我都有*or_()语句中的运算符,并且两个查询都很棒,但我不确切知道为什么.这是参考这一个

python sqlalchemy

1
推荐指数
1
解决办法
88
查看次数