小编jbo*_*boo的帖子

当我调用以下方法并想捕获错误并检查错误代码时，我无法指定错误类型以外的错误类型，因此无法访问错误。代码来自firebase.auth.Error.

方法描述：（方法）firebase.auth.Auth.createUserWithEmailAndPassword(email: string, password: string): firebase.Promise

Specifingfirebase.auth.Auth在当时的工作，但firebase.auth.Error给我一个编译错误。

error TS2345: Argument of type '(error: Error) => void' is not assignable to parameter of type '(a: Error) => any'.
Types of parameters 'error' and 'a' are incompatible.
Type 'Error' is not assignable to type 'firebase.auth.Error'.
Property 'code' is missing in type 'Error'.

this.auth.createUserWithEmailAndPassword(username, password)
                .then( (auth: firebase.auth.Auth) => { return auth; } )
                .catch( (error: firebase.auth.Error) => {

                    let errorCode = error.code;
                    let errorMessage = error.message; …