当我传递文本时,以下代码中的LVALUE和RVALUE在实践上有什么区别?我的意思是,在这种特定的字符串情况下(其中字符串是字符串文字),使用RVALUE(&&)有什么好处吗?
void write_Lvalue(const std::string &text) {
//...
}
void write_Rvalue(const std::string &&text) {
//...
}
int main() {
write_Lvalue("writing the Lvalue");
write_Rvalue("writing the Rvalue");
}
Run Code Online (Sandbox Code Playgroud) 我的C++中有两个函数:一个用于挂起,一个用于恢复线程.在某些情况下,我需要停止所有线程但是当前它没关系,但是当我必须恢复线程时,有时它不起作用,我不是没有原因.看方法:
void CDatabaseMonitor::ResumeAllThreads()
{
DWORD dwCurProc = GetCurrentProcessId();
HANDLE hCurProc = CreateToolhelp32Snapshot(TH32CS_SNAPTHREAD, 0);
if (hCurProc != INVALID_HANDLE_VALUE)
{
THREADENTRY32 te = {0};
te.dwSize = sizeof(te);
if (Thread32First(hCurProc, &te))
{
do
{
if (te.dwSize >= FIELD_OFFSET(THREADENTRY32, th32OwnerProcessID) + sizeof(te.th32OwnerProcessID))
{
if (te.th32ThreadID != m_currentThreadId && te.th32OwnerProcessID == dwCurProc)
{
HANDLE thread = ::OpenThread(THREAD_ALL_ACCESS, FALSE, te.th32ThreadID);
if (thread != NULL)
{
ResumeThread(thread);
CloseHandle(thread);
}
}
}
te.dwSize = sizeof(te);
}
while (Thread32Next(hCurProc, &te));
}
CloseHandle(hCurProc);
}
}
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上面的代码有什么问题吗?有没有办法强制线程唤醒?提前致谢.
当我从Winsock调用connect()函数时,有没有办法减少超时?我想差不多30秒,我想放5秒钟.
我正在执行一些关于移动语义的测试,我的类行为对我来说似乎很奇怪。
鉴于模拟类VecOfInt:
class VecOfInt {
public:
VecOfInt(size_t num) : m_size(num), m_data(new int[m_size]) {}
~VecOfInt() { delete[] m_data; }
VecOfInt(VecOfInt const& other) : m_size(other.m_size), m_data(new int[m_size]) {
std::cout << "copy..." <<std::endl;
std::copy(other.m_data, other.m_data + m_size, m_data);
}
VecOfInt(VecOfInt&& other) : m_size(other.m_size) {
std::cout << "move..." << std::endl;
m_data = other.m_data;
other.m_data = nullptr;
}
VecOfInt& operator=(VecOfInt const& other) {
std::cout << "copy assignment..." << std::endl;
m_size = other.m_size;
delete m_data;
m_data = nullptr;
m_data = new int[m_size];
m_data …Run Code Online (Sandbox Code Playgroud) 请你给点意见好吗?你将做点什么不同的?我的意思是,你认为如果我用 std::task 或 std::mutex、std::condition_variable 等来做会更好吗?我用 2 个标志来控制线程是一种矫枉过正吗?
std::atomic<int> counter = { 0 };
std::atomic<bool> switchFlag = { false };
std::atomic<bool> finished = { false };
constexpr int MAX_NUM = 10;
void increment(){
while (!finished.load()){
if (!switchFlag.load()){
std::cout << "incremented to =" << ++counter << '\n';
switchFlag.store(true);
}
}
}
void print(){
while (!finished.load()) {
if (switchFlag.load()){
std::cout << "counter=" << counter.load() << '\n';
if (counter.load() >= MAX_NUM)
finished.store(true);
switchFlag.store(false);
}
}
}
int main() {
auto t1 = std::thread(increment);
auto …Run Code Online (Sandbox Code Playgroud) 假设有以下场景:
class A {};
class B : public A {};
class C : public A {};
class D : public A {};
template<typename T/*std::enable_if and std::is_base_of here*/> class X {};
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当我宣布 X
然后我想约束typename T必须是 A 的子类,否则我会得到一个编译错误。
int main()
{
X<B> x1 = {}; //should work;
X<C> x2 = {}; //should work;
X<D> x2 = {}; //should work;
X<std::string> = {}; //should generate a compiling error;
X<int> = {}; //should generate a compiling error;
};
Run Code Online (Sandbox Code Playgroud) c++ ×6
c++11 ×4
winapi ×2
inheritance ×1
sockets ×1
stdatomic ×1
stdvector ×1
templates ×1
visual-c++ ×1
winsock ×1