小编Kav*_*ree的帖子

音频使用PHP Jquery上传到文件夹

Hiii每个人.

下面是我的HTML.

<!DOCTYPE html>
<html>
  <head>
    <script src="src/recorder.js"></script>
    <script src="src/Fr.voice.js"></script>
    <script src="js/jquery.js"></script>
    <script src="js/app.js"></script>
  </head>

  <body>
    <div class="center_div">
      <span class="recording_label">Please wait...</span>
      <span class="loader_bg"></span>
      <span class="loader_bg1"></span>

      <br/>
      <audio controls id="audio"></audio>
    </div>  

    <style>
      .center_div {
        width: 500px;
        height: 150px;
        background-color: #f5f5f5;
        border: 1px solid #808080;
        position:absolute;
        top:50%;
        left:50%;
        margin-left:-250px;/* half width*/
        margin-top:-75px;/* half height*/
        padding:25px;
      }

      .recording_label {
        display: block;
        text-align: center;
        padding: 10px;
        font-family: sans-serif;
        font-size: 1.1em;
        margin-bottom: 25px;
      }

      .loader_bg {
        min-width: 100%;
        background: #c5c5c5;
        min-height: 20px;
        display: block;
      } …
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php audio jquery file-upload file

13
推荐指数
1
解决办法
1060
查看次数

cdk虚拟滚动与粘性标题html表格角度

我从后端获取了超过 30000 条记录并在前端列出,因此使用 cdk-virtual-scroll 我可以实现这一目标。我创建了用 cdk-tag 括起来的普通表

          <cdk-virtual-scroll-viewport [itemSize] = "20">
            <div class="result_table">
             <table class="dataframe" border="1">
            <thead>
              <tr>
                <th >
                  Name
                </th>
                <th >
                  Description
                </th>
                <th >
                  Group
                </th>
                <th >
                  Data
                </th>
              </tr>
            </thead>
                <tbody>
                  <tr *cdkVirtualFor ="let data of address_obj_data_holder | filter:searchAddr">
                    <td >
                      {{data.name}}
                    </td>
                                             
                    <td >
                      {{data.description}}
                    </td>
                    <td >
                     {{data.group}}
                    </td> 
                    <td >
                     {{data.data}}
                    </td>
                  </tr>
                </tbody>
              </table>
            </div>
          </cdk-virtual-scroll-viewport>
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如果我这样做,当我向下滚动时,表格标题也会滚动,如果我喜欢,

          <cdk-virtual-scroll-viewport [itemSize] = "20">
            <div class="result_table">
             <table class="dataframe" border="1">
            <thead>
              <tr>
                <th style="width: …
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html css angular6 angular-cdk-virtual-scroll

7
推荐指数
1
解决办法
5950
查看次数

如何从切换按钮是/否获取值并在按钮活动中显示检索数据

大家好,

下面是我的代码来显示切换按钮是/否。我想要做的是基于用户选择我想检索数据。如果他们选择是切换按钮 javascript 变量应该有是字符串,否则没有字符串。

HTML代码

<label class="switch">
  <input class="switch-input" type="checkbox" />
  <span class="switch-label" data-on="Yes" data-off="No"></span> 
  <span class="switch-handle"></span> 
 </label>
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CSS

  .switch {
  position: relative;
  display: block;
  vertical-align: top;
  width: 100px;
  height: 30px;
  padding: 3px;
  margin: 0 10px 10px 0;
  background: linear-gradient(to bottom, #eeeeee, #FFFFFF 25px);
  background-image: -webkit-linear-gradient(top, #eeeeee, #FFFFFF 25px);
  border-radius: 18px;
  box-shadow: inset 0 -1px white, inset 0 1px 1px rgba(0, 0, 0, 0.05);
  cursor: pointer;
}
.switch-input {
  position: absolute;
  top: 0;
  left: 0;
  opacity: 0;
}
.switch-label { …
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html javascript css jquery android

2
推荐指数
1
解决办法
3万
查看次数

laravel中的Ajax 419状态错误

在此输入图像描述我尝试使用AJax,Jquery,Laravel上传图像.在这里,我尝试了这么多解决方案,但我得到419错误,在某些情况下得到500内部错误.

我试过的代码是

<form method="POST" id="needs" novalidate enctype="multipart/form-data">
            {{csrf_field()}}
                <input name="image1" id="image1" type="file" class="form-control" required="" />
                <br>
                <input type="file" name="image2" id="image2" class="form-control" required/>
                <br>
                <input type="file" name="image3" id="image3" class="form-control" required/>
                <br>
                <input type="file" name="image4" id="image4" class="form-control" required/>
                <br>
                <input type="file" name="image5" id="image5" class="form-control" required />
                <br>
                <button type="button" id="upload_image" name="upload_image" class="btn btn-lg btn-success" onclick="image_up();">Upload</button>
              </form>
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jQuery的:

function image_up()
{
  alert("Uploading start");
  $.ajax({
    headers: {
          'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
          },
        url: "{{route('collage.store')}}",
        type: 'POST',
        data : new FormData($(this)[0]),
        dataType: "json",
        cache : false,
    processData: …
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php ajax jquery laravel laravel-5

2
推荐指数
1
解决办法
971
查看次数