我是C#的新手,所以我真的不知道如何制作它,但在C++中,我就是这样做的
template <typename T> writeInt(int location, T value){
*(T*)&buffer[location] = value;
}
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在C#我试图做同样的事情
public void WriteInt<T>(int location,T value)
{
(T)buffer[location] = value;
}
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但是我发现了这个错误,Cannot convert type 'byte' to 'T'
所以我该怎么办呢,谢谢
while(thingA is true)
{
}
if(thingA is not true)
{
make thingA true
then back to looping
}
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我的问题是如果循环是真的它将继续循环但如果不是我将通过其他代码使其成为真,之后我希望它再次循环.我可以这样做吗??
我如何提供一个带载矢量参数的重载?
void res(uint8_t* buffer, int len)
{
std::vector<uint8_t> buf( buffer, buffer + len );
// here i want to pass buf as uint8_t* to onther func
pack((uint8_t*)buf, len));// error
}
IntelliSense: no suitable conversion function from "std::vector<uint8_t, std::allocator<uint8_t>>" to "uint8_t *"
Run Code Online (Sandbox Code Playgroud) STARTUPINFO si;
PROCESS_INFORMATION pi;
memset(&si, 0, sizeof(si));
memset(&pi, 0, sizeof(pi));
si.cb = sizeof(si);
LPCWSTR procName =(LPCWSTR)"D:\\test dir 1\\Calc.exe";
LPWSTR procArg =(LPWSTR)"blacknull";
if(CreateProcess(procName,procArg,0,0,0,CREATE_DEFAULT_ERROR_MODE,0,0,&si,&pi))
{
//do some work
}
printf( "CreateProcess failed (%d).\n", GetLastError());
system("Pause");
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它不断抛出错误(2) - > The System cannot find the file specified.
我不知道出了什么问题.我也尝试在同一个Dir中使用"Calc.exe".但它不起作用.
在那儿 MulDiv
WINBASEAPI
int
WINAPI
MulDiv(
_In_ int nNumber,
_In_ int nNumerator,
_In_ int nDenominator
);
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在C#或相当于它?
或者我应该实施它?
编辑:没有PInvoking !!
我正在尝试制作如下query功能:
public function Query( $sql, $params = array() ) {
$this->error = false;
if ( $this->query = $this->pdo->prepare( $sql ) ) {
for ( $i = 0, $size = count( $params ); $i < $size; $i ++ ) {
echo $i;
$this->query->bindValue( $i, $params[ $i ] );
}
if ( $this->query->execute() ) {
echo 'suc';
}
}
}
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并称之为:
$mysql->Query( "SELECT * FROM `client_info` WHERE `name` = ? AND `password`= ?", array(
'test',
'test'
) );
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结果是:
Warning: …Run Code Online (Sandbox Code Playgroud) 可能重复:
如何在C++循环中生成不同的随机数?
在这段代码中:
int Randtest(int len)
{
int test[100]={};
for(int i=0;i<len;i++)
{
srand ( time(NULL) );
cout <<(test[i]=rand()%10);
}
}
int main()
{
Randtest(8);
}
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输出将始终是一系列重复的数字,如22222222或11111111.如何让它产生八个随机数?
#ifndef _ClientSocket_H_
#define _ClientSocket_H_
#include "Includes.h"
#include "LOGMSGs.h"
class cSocket
{
public:
cSocket();
bool Open();
bool Listen(char *OnIP,int OnPort);
void Send(char *MSG, int len);
void Recv(char *MSG,int len);
void Close();
protected:
SOCKET cSock;
const int SndBuf;
};
#endif
#include "ClientSocket.h"
bool cSocket::Open()
{
WSADATA wsaData;
int err;
if((err =WSAStartup(0x202, &wsaData)) !=0)
{
Error("Init WSAStartup() failed[%d].", err);
return false;
}
return true;
}
bool cSocket::Listen(char *OnIP,int OnPort)
{
if(Open())
{
//Create the main socket
cSock=socket(AF_INET, SOCK_STREAM, 0);
if(cSock==INVALID_SOCKET)
{
int err …Run Code Online (Sandbox Code Playgroud) 使用boost :: asio的以下代码将无法编译:
#ifndef _SERVER_H_
#define _SERVER_H_
#include "Connection.h"
class Server
{
public:
Server(boost::asio::io_service& io_service);
private:
void start_accept();
void handle_accept(Connection::pointer new_connection,const boost::system::error_code& error);
boost::asio::ip::tcp::acceptor acceptor_;
};
#endif
-------------------------------------------------------------------------------------------------
#include "Server.h"
Server::Server(boost::asio::io_service& io_service)
: acceptor_(io_service, boost::asio::ip::tcp::endpoint(boost::asio::ip::tcp::v4(), 9985)){
start_accept();
}
void Server::start_accept(){
Connection::pointer new_connection =
Connection::create(acceptor_.io_service());
acceptor_.async_accept(new_connection->socket(),
boost::bind(&Server::handle_accept, this, new_connection,
boost::asio::placeholders::error));
}
void Server::handle_accept(Connection::pointer new_connection,const boost::system::error_code& error){
if (!error)
{
new_connection->start();
start_accept();
}
}
--------------------------------------------------------------------------------------------------
#include <Server.h>
#include <iostream>
int main()
{
try
{
boost::asio::io_service io_service;
Server server1(io_service);
io_service.run();
}
catch (std::exception& …Run Code Online (Sandbox Code Playgroud) 我已经下载了ffmpegfor 的静态版本,Windows并尝试获取所有我搜索过的声音设备(输入/输出),并找到了此命令来检索音频设备,但是当我使用它时ffmpeg arecord -l,它显示了此错误
Unrecognized option 'l'.
Error splitting the argument list: Option not found
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这里缺少什么?
是否有可能一些如何使Text的的Textbox无形或隐藏,这样用户不能看到它,但它获得的来自用户的输入/键?
bool Connection::Receive(){
std::vector<uint8_t> buf(1000);
boost::asio::async_read(socket_,boost::asio::buffer(buf,1000),
boost::bind(&Connection::handler, this, boost::asio::placeholders::error, boost::asio::placeholders::bytes_transferred));
int rcvlen=buf.size();
ByteBuffer b((std::shared_ptr<uint8_t>)buf.data(),rcvlen);
if(rcvlen <= 0){
buf.clear();
return false;
}
OnReceived(b);
buf.clear();
return true;
}
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该方法工作正常,但仅当我在其中创建断点时才有效。等待接收的时间是否有问题?没有断点,什么也收不到。