请帮助我找到一种优雅的方式来获取没有扩展名的文件路径; 从路径或其他东西切断文件扩展名.
我有这样的 nodejs 代码:
var mysql = require('mysql2/promise');
mysql.createConnection({
host: "localhost",
user: "root",
password: "123123",
database: "mydatabase"
})
.then((connection) => connection.execute("SELECT * FROM mytable"))
.then(([rows, fields]) => {
console.log(rows);
});
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当我执行它时,应用程序打印数据库行数组,然后仍在运行。似乎发生这种情况是因为连接未释放。之后如何释放console.log?
我试过这种方式:
var mysql = require('mysql2/promise');
mysql.createConnection({
host: "localhost",
user: "root",
password: "123123",
database: "mydatabase"
})
.then((connection) => {
connection.execute("SELECT * FROM mytable")
.then(([rows, fields]) => {
console.log(rows);
connection.release();
});
});
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但结果是TypeError: this.connection.release is not a function。
对不起我的英语不好。
有任何想法吗?
我正在Rust中编写一个带有控制台提示界面的进程内存扫描程序.
我需要扫描仪类型,如winapi扫描仪或ring0驱动程序扫描仪,所以我试图实现多态.
我现在有以下结构:
pub trait Scanner {
fn attach(&mut self, pid: u32) -> bool;
fn detach(&mut self);
}
pub struct WinapiScanner {
pid: u32,
hprocess: HANDLE,
addresses: Vec<usize>
}
impl WinapiScanner {
pub fn new() -> WinapiScanner {
WinapiScanner {
pid: 0,
hprocess: 0 as HANDLE,
addresses: Vec::<usize>::new()
}
}
}
impl Scanner for WinapiScanner {
fn attach(&mut self, pid: u32) -> bool {
let handle = unsafe { OpenProcess(PROCESS_ALL_ACCESS, FALSE, pid) };
if handle == 0 as HANDLE { …Run Code Online (Sandbox Code Playgroud)