小编DS *_*S R的帖子

一个简单的程序，用于计算数字平方并存储结果：

    import time
    from joblib import Parallel, delayed
    import multiprocessing

    array1 = [ 0 for i in range(100000) ]

    def myfun(i):
        return i**2

    #### Simple loop ####
    start_time = time.time()

    for i in range(100000):
        array1[i]=i**2

    print( "Time for simple loop         --- %s seconds ---" % (  time.time()
                                                               - start_time
                                                                 )
            )
    #### Parallelized loop ####
    start_time = time.time()
    results = Parallel( n_jobs  = -1,
                        verbose =  0,
                        backend = "threading"
                        )(
                        map( delayed( myfun ),
                             range( 100000 )
                             )
                        ) …