我有两个变量:
$lang = hu
$image = image.jpg
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如何在php中将image.jpg替换为image_hu.jpg?也许用str_replace?但是怎么样?
我有这个代码
...
SERVERCONNECTION=$(wget --quiet -O - http://xx:yy@127.0.0.1:10001/server | grep connections | awk '{print $36}')
有时url得到响应,然后我想杀死wget进程并将SERVERCONNECTIION变量设置为0.
可以使用bash进行以下过程吗?
"Id";"Vzor";"Name";"Number";"Number2";"Ship"
"00041534";"MGKHTYE";"2014 TREK TYAX EXPERT, GREY/YELLOW";"100";"100,30";"A"
"00041535";"MGKHTYE";"2014 TREK TYAX EXPERT 29 , BLACK/RED";"100";"453,30";"A"
"00041531";"MGKHTYSP";"2014 OPS TYAX SPORT, WHITE/GREY";"100,90";"306,60";"A"
"00046024";"MGKFAR";"2015 OPS ARGUS, DARK TEAL";"899,90";"100,90";"A"
"00046088";"MGKHFB";"2015 TREK FIREBALL 24 , BLACK";"100,90";"239,90";"A"
"00046026";"MGKHFB";"2015 OPS FIREBALL 26 , BLUE";"100,90";"359,90";"A"
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将列添加到名为"Category"的第一行和(我不能做的)各个行,从第3列添加该列的前两个单词(这将是类别名称):
"Id";"Vzor";"Name";"Number";"Number2";"Ship";"Category"
"00041534";"MGKHTYE";"2014 TREK TYAX EXPERT, GREY/YELLOW";"100";"100,30";"A";"2014 TREK"
"00041535";"MGKHTYE";"2014 TREK TYAX EXPERT 29 , BLACK/RED";"100";"453,30";"A";"2014 TREK"
"00041531";"MGKHTYSP";"2014 OPS TYAX SPORT, WHITE/GREY";"100,90";"306,60";"A";"2014 OPS"
"00046024";"MGKFAR";"2015 OPS ARGUS, DARK TEAL";"899,90";"100,90";"A";"2015 OPS"
"00046088";"MGKHFB";"2015 TREK FIREBALL 24 , BLACK";"100,90";"239,90";"A";"2015 TREK"
"00046026";"MGKHFB";"2015 OPS FIREBALL 26 , BLUE";"100,90";"359,90";"A";"2015 OPS"
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猛击力量!