小编Tob*_*obi的帖子

如果键不存在,如何插入到 DynamoDb

我只想将 id + 一些值添加到 DynamoDb 一次。如果 id 已经存在,它应该什么都不做或更新

我可以去

search 

if not found > insert

if found > do nothing or update (for now do nothing is fine)
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但希望有更好的方法来做到这一点。id 应该是要检查的关键。

这是节点中的代码:

const dynamodbParams = {
        TableName: process.env.DYNAMODB_TABLE_BLICKANALYTICS,
        Item: {
          id: userId,
          createdAt: timestamp
        },
      };

      dynamoDb.put(dynamodbParams).promise()
      .then(data => {
        console.log('saved: ', dynamodbParams);
      })
      .catch(err => {
        console.error(err);
      });  
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我在 yml 中使用它。不知道yml有没有设置这个选项

resources:
  Resources:
    DynamoDbTableExpenses:
      Type: 'AWS::DynamoDB::Table'
      DeletionPolicy: Retain
      Properties:
        AttributeDefinitions:
          -
            AttributeName: id
            AttributeType: S
          -  
            AttributeName: createdAt
            AttributeType: N …
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amazon-web-services node.js amazon-dynamodb

19
推荐指数
1
解决办法
3万
查看次数

如何一次“取消运行”所有计划的 github 操作?

是否有一个选项可以同时取消一个存储库中所有计划的 github 操作的运行。总是去这里取消运行需要很多点击。 在此输入图像描述

github github-actions

11
推荐指数
3
解决办法
4727
查看次数

Pandas数据框作为json的烧瓶模板

我尝试在烧瓶模板中输出pandas数据帧.我的想法是将它转换为json然后遍历表格

我测试了这个

jsonfiles = df.to_json(orient='records')

return render_template('index.html', ctrsuccess=jsonfiles)
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在模板中,我尝试输出如下:

        {%if ctrsuccess %}
        <div class="table-responsive">
            <table class="table table-striped">
                <tbody>
                    {%for ctrrow in ctrsuccess %}
                    <tr>
                        <td>{{ ctrrow['positionint'] }}</td>
                    </tr>
                    {%endfor%}
                </tbody>
            </table>
        </div>
        {%endif%}
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在模板中,如果我只是绘制ctrsuccess,我会得到一个正确的json.但桌子是空的

[{"positionint":1.0,"clicks":1138.0,"impressions":4768.0,"ctr":0.2386744966,"clickCtr10p":1251.8,"clickCtr50p":1707.0,"clickCtr100p":2276.0},{"positionint":2.0,"clicks":3160.0,"impressions":49899.0,"ctr":0.0633279224,"clickCtr10p":3476.0,"clickCtr50p":4740.0,"clickCtr100p":6320.0},{"positionint":3.0,"clicks":1255.0,"impressions":50020.0,"ctr":0.025089964,"clickCtr10p":1380.5,"clickCtr50p":1882.5,"clickCtr100p":2510.0},{"positionint":4.0,"clicks":363.0,"impressions":39077.0,"ctr":0.0092893518,"clickCtr10p":399.3,"clickCtr50p":544.5,"clickCtr100p":726.0},{"positionint":5.0,"clicks":216.0,"impressions":18419.0,"ctr":0.011727021,"clickCtr10p":237.6,"clickCtr50p":324.0,"clickCtr100p":432.0},{"positionint":6.0,"clicks":307.0,"impressions":15447.0,"ctr":0.0198744093,"clickCtr10p":337.7,"clickCtr50p":460.5,"clickCtr100p":614.0},{"positionint":7.0,"clicks":248.0,"impressions":24709.0,"ctr":0.0100368287,"clickCtr10p":272.8,"clickCtr50p":372.0,"clickCtr100p":496.0},{"positionint":8.0,"clicks":236.0,"impressions":26853.0,"ctr":0.0087885897,"clickCtr10p":259.6,"clickCtr50p":354.0,"clickCtr100p":472.0},{"positionint":9.0,"clicks":139.0,"impressions":26577.0,"ctr":0.0052300862,"clickCtr10p":152.9,"clickCtr50p":208.5,"clickCtr100p":278.0},{"positionint":10.0,"clicks":23.0,"impressions":2046.0,"ctr":0.0112414467,"clickCtr10p":25.3,"clickCtr50p":34.5,"clickCtr100p":46.0},{"positionint":null,"clicks":7085.0,"impressions":257815.0,"ctr":null,"clickCtr10p":7793.5,"clickCtr50p":10627.5,"clickCtr100p":14170.0},{"positionint":null,"clicks":null,"impressions":null,"ctr":null,"clickCtr10p":1417.0,"clickCtr50p":7085.0,"clickCtr100p":14170.0}]
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python json flask pandas

4
推荐指数
1
解决办法
4517
查看次数

firebase 函数中的 Puppeteer 无法启动 chrome

我尝试在 firebase 函数中运行 puppeteer。据我了解 https://github.com/GoogleChrome/puppeteer/blob/master/docs/troubleshooting.md#running-puppeteer-on-google-cloud-functions 它应该可以添加

 "engines": {
    "node": "8"
  },
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在 package.json 中。我得到了它使用 firebase deploy 的积极反馈

 functions: updating Node.js 8 function helloWorld(us-central1)...
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可悲的是它兑现了

Error: Error: Failed to launch chrome!
[0408/080847.149912:ERROR:zygote_host_impl_linux.cc(89)] Running as root without --no-sandbox is not supported. See https://crbug.com/638180.


TROUBLESHOOTING: https://github.com/GoogleChrome/puppeteer/blob/master/docs/troubleshooting.md

    at startPuppeteer.then.then.then.catch.error (/srv/index.js:42:15)
    at <anonymous>
    at process._tickDomainCallback (internal/process/next_tick.js:229:7)

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在本地测试了相同的代码。

那是失败的云函数代码。

const functions = require('firebase-functions');

const puppeteer = require('puppeteer');
let browser = ""
let page = ""

const startPuppeteer = async () => {
    browser = await puppeteer.launch(); …
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javascript google-chrome node.js firebase puppeteer

0
推荐指数
1
解决办法
2783
查看次数