小编Udd*_*ers的帖子

基础帐户

class BaseAccount(models.Model):
user = models.ForeignKey(User, unique=True)

def __unicode__(self):
    """
    Return the unicode representation of this customer, which is the user's
    full name, if set, otherwise, the user's username
    """
    fn = self.user.get_full_name()
    if fn:
        return fn
    return self.user.username

def user_name(self):
    """
    Returns the full name of the related user object
    """
    return self.user.get_full_name()

def email(self):
    """
    Return the email address of the related user object
    """
    return self.user.email

def is_store(self):
    #try:
    #   self.user.is_store
    #    return True
    #except ObjectDoesNotExist:
    # …

通常,如果我正在写一个sql语句,我会做这样的事情,

    SELECT * FROM (django_baseaccount LEFT JOIN django_account ON django_baseaccount.user_id = django_account.baseaccount_ptr_id)
LEFT JOIN django_address ON django_account.baseaccount_ptr_id = django_address.user_id;name 

我如何把这个用于使用API​​查询数据库的Djagno方式,即

TradeDownloads.objects.filter(online=1)[:6]

我的模特基础帐户

class BaseAccount(models.Model):
user = models.ForeignKey(User, unique=True)

def __unicode__(self):
    """
    Return the unicode representation of this customer, which is the user's
    full name, if set, otherwise, the user's username
    """
    fn = self.user.get_full_name()
    if fn:
        return fn
    return self.user.username

def user_name(self):
    """
    Returns the full name of the related user object
    """
    return self.user.get_full_name()

def email(self):
    """
    Return the …

使用jQuery我试图确定是否<div>有内容,或者,如果它确实那么我想什么都不做,但如果没有,那么我想添加display:none到它或.hide().以下是我的想法,

if ($('#left-content:contains("")').length <= 0) { $("#left-content").css({'display':'none'}); }

这根本不起作用,如果div没有内容然后它只是出现,可以提出任何建议吗？

我正在使用基于Django背面构建的Python站点(非常棒的框架,无法让我的头脑绕过python),我希望拆分从数据库返回的字符串,我希望它在第一个空格出现时被拆分所以我试过这样的事,

{{product.name.split(' ' ,1)}}

这不起作用,我得到这个堆栈跟踪,

    Environment:

Request Method: GET
Request URL: http://website.co.uk/products/
Django Version: 1.1.1
Python Version: 2.5.2
Installed Applications:
['django.contrib.auth',
 'django.contrib.admin',
 'django.contrib.contenttypes',
 'django.contrib.sessions',
 'django.contrib.sites',
 'website.news',
 'website.store_locator',
 'website.css_switch',
 'website.professional',
 'website.contact',
 'website.shop',
 'tinymce',
 'captcha']
Installed Middleware:
('django.middleware.common.CommonMiddleware',
 'django.contrib.sessions.middleware.SessionMiddleware',
 'django.contrib.auth.middleware.AuthenticationMiddleware')


Template error:
In template /var/www/website/src/website/shop/templates/category.html, error at line 6
   Could not parse the remainder: '(' ',1)' from 'product.name.split(' ',1)'
   1 : {% extends "shopbase.html" %}


   2 : {% block pageid %}shop{%endblock%}


   3 : {% block right-content %}


   4 :  <div class="products">


   5 …

class person {

    var $name;
    var $email;

    //Getters
    function get_name() { return $this->name; }
    function get_email() { return $this->email; }

    //Setters
    function set_name( $name ) { $this->name = $name; }

    function set_email( $email ) {

        if ( !eregi("^([0-9,a-z,A-Z]+)([.,_,-]([0-9,a-z,A-Z]+))*[@]([0-9,a-z,A-Z]+)([.,_,-]([0-9,a-z,A-Z]+))*[.]([0-9,a-z,A-Z]){2}([0-9,a-z,A-Z])*$", $email ) ) {
            return false;
        } else { 
            $this->email = $email;
            return true;
        }

    }//EOM set_email

}//EOC person

我目前正在使用python/django网站,目前我有一个看起来像这样的模板

 {% extends "shopbase.html" %}
{% block pageid %}products{% endblock %}
{% block right-content %}

<img src="{{MEDIA_URL}}/local/images/assets/products.png" alt="Neal and Wolf News" class="position"/>
    <div class="products">
    <form method="post" action="{% url category category.slug %}">
    {% for product in category.products.all %}
        <div class="{% cycle 'clear' '' '' %}">
            <img src="{{MEDIA_URL}}{{download.mini.thumbnail}}" alt="{{product.name}}" class="thumbnail"/>
            <h3><a href="{% url shop.views.product category.slug product.slug %}">{{ product.product_type_name }}</a></h3>
            <p class="strap">{{ product.product_sub_name }}</p>
            <p>{{ product.strap }}</p>
            <ul class="clear">
                <li class="price"><b>&pound;{{product.price}}</b></li>
                <li class="quantity">
                    <select name="quantity_{{product.id}}">
                        <option label="1" value="1">1</option>
                        <option label="2" value="2">2</option>
                        <option label="3" …

我目前正在codeigniter中建立一个网站,这是一个页面网站,基本上是一个用户进入页面,他们使用该菜单中的主菜单创建,他们选择了他们想要查看的网站的哪些部分,并点击关联链接...点击这些链接应该在他们自己的手册菜单中显示内容.

我的问题是我认为最简单的方法是使用jquery和ajax加载选定的视图？如果我在错误的路线上什么是更好的解决方案,我也找不到任何关于使用ajax加载视图的内容,是否有人有任何建议？

当我尝试在我的Python网站上查看一些数据时,我有这个堆栈跟踪错误,有人可以告诉我什么是问题我是如此迷失

   Environment:

Request Method: GET
Request URL: http://mywesbite.genericdomain.co.uk/admin/shop/passwordresetrequest/4/
Django Version: 1.1.1
Python Version: 2.5.2
Installed Applications:
['django.contrib.auth',
 'django.contrib.admin',
 'django.contrib.contenttypes',
 'django.contrib.sessions',
 'django.contrib.sites',
 'mywebsite.news',
 'mywebsite.store_locator',
 'mywebsite.css_switch',
 'mywebsite.professional',
 'mywebsite.contact',
 'mywebsite.shop',
 'tinymce',
 'captcha']
Installed Middleware:
('django.middleware.common.CommonMiddleware',
 'django.contrib.sessions.middleware.SessionMiddleware',
 'django.contrib.auth.middleware.AuthenticationMiddleware')


Template error:
In template /usr/lib/python2.5/site-packages/django/contrib/admin/templates/admin/change_form.html, error at line 20
   Caught an exception while rendering: 'PasswordResetRequest' object has no attribute 'date'
   10 : 


   11 : {% block coltype %}{% if ordered_objects %}colMS{% else %}colM{% endif %}{% endblock %}


   12 : 


   13 : {% block bodyclass %}{{ opts.app_label …

我有一个小的自定义缩略图库.点击缩略图我想获得更大版本的图像.要做到这一点,我得到img的src.有了这个我想用另一个字符串替换字符串的某个部分.例如,缩略图的源可能如下所示:

/media/uploads/headshots/width_60_259850_10150280251835435_717615434_9570015_4084479_n.jpg

我需要更换width_60_用width_104_.这可能与Javascript？

我有以下代码,

$(".delete.red").live("click", function () {
    var self = $(this);
    var loadUrl = $(this).attr('href');
    alert("clicked");
    //var interestParents = self.parents('div:eq(4)').attr("id");
    $.ajax({
        type: "POST",
        url: loadUrl,
        dataType: "json"
    }).success(function (msg) {
        alert(msg);
        self.parent().parent().parent().parent().parent().parent().remove();
        $(".selected strong").text(msg.icount)

    });
    return false;
});

这个代码在点击它向请点击的链接href发送请求的链接时做了什么,它应该找到该链接的最外层父节点并从标记中删除它自己.

但是请求没有得到done()我现在得到的功能反馈它几乎就好像它没有被调用,这看起来很奇怪,因为当我查看网络选项卡时,我可以看到链接href已被访问,我可以看到200 OK回应.

Waht正在进行中？