我以为is操作员检查对象id的相等性.但它似乎并非如此:
>>> class A(object):
... def f(): return 1
... def g(): return 2
...
>>> a = A()
>>> a.f is a.g
False
>>> id(a.f) == id(a.g)
True
Run Code Online (Sandbox Code Playgroud) 当我设置属性时,getattr结果会id更改为值id.当我设置方法时,getattr结果id不会改变.为什么?
class A (object):
a = 1
a = 42
print id(getattr(A, 'a'))
print id(a)
setattr(A, 'a', a)
print id(getattr(A, 'a'))
# Got:
# 36159832
# 36160840
# 36160840
class B (object):
def b(self):
return 1
b = lambda self: 42
print id(getattr(B, 'b'))
print id(b)
setattr(B, 'b', b)
print id(getattr(B, 'b'))
# Got:
# 140512684858496
# 140512684127608
# 140512684858496
Run Code Online (Sandbox Code Playgroud) python ×2