我使用Hibernate作为持久性提供程序,并使用JPA 2为我的实体建模.
现在提出了一个问题,我希望你能帮助我.
在我的应用程序中,您可以打开一个游戏,在其中创建一组玩家并在地图上四处走动(瓦片(2d)).
首先我的实体定义:游戏:
@Entity
public class Game implements Serializable {
@Id
@SequenceGenerator(name = "gen_gameid", sequenceName = "seq_gameid")
@GeneratedValue(generator="gen_gameid")
private long gameid;
/**
* Playing Characters.
*/
@OneToMany(mappedBy = "game")
private List<Character> characters;
private int round = 0;
@OneToMany(mappedBy="game")
private List<Tile> tiles;
@OneToMany(mappedBy="game")
private List<Group> group;
平铺(将从模板创建一个平铺,只属于一个游戏):
@Entity @IdClass(TileId.class)
public class Tile implements Serializable{
private static final long serialVersionUID = 2039974286110729270L;
@Id
private int x;
@Id
private int y;
@Id @ManyToOne @JoinColumn(name="gameid")
private Game game;
@OneToOne(mappedBy="tile")
private Character character; …我从jboss 7.1迁移到wildfly,我的数据源有一些问题.
10:04:37,900 INFO [org.wildfly.extension.undertow] (ServerService Thread Pool -- 49) JBAS017502: Undertow 1.0.0.Final starting
10:04:37,901 INFO [org.wildfly.extension.undertow] (MSC service thread 1-2) JBAS017502: Undertow 1.0.0.Final starting
10:04:37,903 INFO [org.jboss.as.webservices] (ServerService Thread Pool -- 50) JBAS015537: Activating WebServices Extension
10:04:37,904 INFO [org.jboss.as.security] (MSC service thread 1-3) JBAS013170: Current PicketBox version=4.0.20.Final
10:04:37,913 INFO [org.jboss.as.connector.subsystems.datasources] (ServerService Thread Pool -- 28) JBAS010404: Deploying non-JDBC-compliant driver class org.postgresql.Driver (version 9.0)
10:04:37,919 INFO [org.jboss.as.connector.deployers.jdbc] (MSC service thread 1-6) JBAS010417: Started Driver service with driver-name = postgresql
10:04:37,924 …在从JBoss 7迁移到WildFly的过程中,我遇到了另一个问题.调用受@RolesAllowed("ADMIN")我保护的休息服务时会收到以下错误:
13:46:44,359 ERROR [org.jboss.as.ejb3.invocation] (default task-1) JBAS014134: EJB Invocation failed on component TestFacade for method public java.lang.String net.dice.facade.TestFacade.generateTestdata(): javax.ejb.EJBAccessException: JBAS013323: Invalid User
at org.jboss.as.ejb3.security.SecurityContextInterceptor$1.run(SecurityContextInterceptor.java:66) [wildfly-ejb3-8.0.0.Final.jar:8.0.0.Final]
at org.jboss.as.ejb3.security.SecurityContextInterceptor$1.run(SecurityContextInterceptor.java:46) [wildfly-ejb3-8.0.0.Final.jar:8.0.0.Final]
at org.jboss.as.ejb3.security.SecurityContextInterceptor.processInvocation(SecurityContextInterceptor.java:92) [wildfly-ejb3-8.0.0.Final.jar:8.0.0.Final]
at org.jboss.invocation.InterceptorContext.proceed(InterceptorContext.java:309)
at org.jboss.as.ejb3.component.interceptors.ShutDownInterceptorFactory$1.processInvocation(ShutDownInterceptorFactory.java:64) [wildfly-ejb3-8.0.0.Final.jar:8.0.0.Final]
at org.jboss.invocation.InterceptorContext.proceed(InterceptorContext.java:309)
at org.jboss.as.ejb3.component.interceptors.LoggingInterceptor.processInvocation(LoggingInterceptor.java:59) [wildfly-ejb3-8.0.0.Final.jar:8.0.0.Final]
at org.jboss.invocation.InterceptorContext.proceed(InterceptorContext.java:309)
at org.jboss.as.ee.component.NamespaceContextInterceptor.processInvocation(NamespaceContextInterceptor.java:50)
at org.jboss.invocation.InterceptorContext.proceed(InterceptorContext.java:309)
at org.jboss.as.ejb3.component.interceptors.AdditionalSetupInterceptor.processInvocation(AdditionalSetupInterceptor.java:55) [wildfly-ejb3-8.0.0.Final.jar:8.0.0.Final]
at org.jboss.invocation.InterceptorContext.proceed(InterceptorContext.java:309)
at org.jboss.invocation.ContextClassLoaderInterceptor.processInvocation(ContextClassLoaderInterceptor.java:64)
at org.jboss.invocation.InterceptorContext.proceed(InterceptorContext.java:309)
at org.jboss.invocation.InterceptorContext.run(InterceptorContext.java:326)
at org.wildfly.security.manager.WildFlySecurityManager.doChecked(WildFlySecurityManager.java:448)
at org.jboss.invocation.AccessCheckingInterceptor.processInvocation(AccessCheckingInterceptor.java:61)
at org.jboss.invocation.InterceptorContext.proceed(InterceptorContext.java:309)
at org.jboss.invocation.InterceptorContext.run(InterceptorContext.java:326)
at org.jboss.invocation.PrivilegedWithCombinerInterceptor.processInvocation(PrivilegedWithCombinerInterceptor.java:80)
at org.jboss.invocation.InterceptorContext.proceed(InterceptorContext.java:309)
at org.jboss.invocation.ChainedInterceptor.processInvocation(ChainedInterceptor.java:61)
at org.jboss.as.ee.component.ViewService$View.invoke(ViewService.java:185)
at org.jboss.as.ee.component.ViewDescription$1.processInvocation(ViewDescription.java:182)
at …我正在尝试将jacoco集成到我们的ant构建中,并使用一个简单的测试项目对其进行评估.
编译和其他输出看起来很有希望,但是当我查看覆盖范围时,它总是为零.
package alg;
public class SpecialAlgorithm {
public SpecialAlgorithm() {}
public int uncoveredMethod(int i) {
return i * i;
}
public int sum(int i, int j) {
return i + j;
}
}
测试用例:
package alg;
import static org.junit.Assert.assertEquals;
import org.junit.Test;
import alg.SpecialAlgorithm;
public class SpecialAlgorithmTest {
@Test
public void testSum() {
SpecialAlgorithm alg = new SpecialAlgorithm();
int sum = alg.sum(1, 2);
assertEquals(3, sum);
}
}
Ant脚本:
<project xmlns:jacoco="antlib:org.jacoco.ant" name="Code Coverage with JaCoCo"
default="rebuild">
<property name="src.dir" location="../java" />
<property …我有一个web-app(Tomcat 6,log4j 1.2.16),它以一个监听器开头.取消部署应用程序会引发以下异常:
INFO (HqListener.java:28) - HqListener exited!
log4j:ERROR log4j called after unloading, see http://logging.apache.org/log4j/1.2/faq.html#unload.
java.lang.IllegalStateException: Class invariant violation
at org.apache.log4j.LogManager.getLoggerRepository(LogManager.java:199)
at org.apache.log4j.LogManager.getLogger(LogManager.java:228)
at org.apache.log4j.Logger.getLogger(Logger.java:117)
at com.mchange.v2.log.log4j.Log4jMLog.getMLogger(Log4jMLog.java:51)
at com.mchange.v2.log.MLog.getLogger(MLog.java:145)
at com.mchange.v2.sql.SqlUtils.<clinit>(SqlUtils.java:37)
at com.mchange.v2.c3p0.DataSources.pooledDataSource(DataSources.java:290)
at com.mchange.v2.c3p0.DataSources.pooledDataSource(DataSources.java:316)
at org.hibernate.connection.C3P0ConnectionProvider.configure(C3P0ConnectionProvider.java:181)
at org.hibernate.connection.ConnectionProviderFactory.newConnectionProvider(ConnectionProviderFactory.java:143)
at org.hibernate.ejb.InjectionSettingsFactory.createConnectionProvider(InjectionSettingsFactory.java:51)
at org.hibernate.cfg.SettingsFactory.buildSettings(SettingsFactory.java:90)
at org.hibernate.cfg.Configuration.buildSettingsInternal(Configuration.java:2863)
at org.hibernate.cfg.Configuration.buildSettings(Configuration.java:2859)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1870)
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:906)
at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:57)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:48)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:32)
at net.hq.util.Db.init(Db.java:15)
at net.hq.process.ConnectionGateway.run(ConnectionGateway.java:89)
at java.lang.Thread.run(Thread.java:662)
Exception in thread "HQ Gateway Thread" java.lang.NullPointerException
at net.hq.process.ConnectionGateway.run(ConnectionGateway.java:129)
at java.lang.Thread.run(Thread.java:662)
Jul 3, 2011 3:03:53 AM org.apache.catalina.core.StandardContext …问题是我的实体中有两个袋子,我想在我的jsf前端显示(后面的Spring,所以没有延迟加载).所以我必须急切地获取它们以在这样的列表中显示信息:
将两个列表都置于渴望之中并不起作用.所以我尝试了一下fetch join.它允许我获取一个列表,但是当我添加第二个列表时,我得到了已知的"无法获取多个包"错误.
Hibernate可以在查询中处理两个fetch连接吗？
public class PointOfInterest
@OneToMany(mappedBy="poi")
private List<PointOfInterestLabel> labels = new ArrayList<PointOfInterestLabel>();
@ManyToMany
private List<Tag> tags = new ArrayList<Tag>();
我的获取加入:
SELECT DISTINCT p from PointOfInterest p
left join fetch p.labels
left join fetch p.tags WHERE p.figure = :figure
在启动时,我的hibernate工厂的创建失败了:
Caused by: org.hibernate.loader.MultipleBagFetchException: cannot simultaneously fetch multiple bags
at org.hibernate.loader.BasicLoader.postInstantiate(BasicLoader.java:94)
at org.hibernate.loader.hql.QueryLoader.<init>(QueryLoader.java:123)
at org.hibernate.hql.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:206)
at org.hibernate.hql.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:136)
at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:101)
at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:80)
at org.hibernate.engine.query.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:98)
at org.hibernate.impl.SessionFactoryImpl.checkNamedQueries(SessionFactoryImpl.java:557)
at org.hibernate.impl.SessionFactoryImpl.<init>(SessionFactoryImpl.java:422)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1385)
at org.hibernate.cfg.AnnotationConfiguration.buildSessionFactory(AnnotationConfiguration.java:954)
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:883)
... 55 more
我使用REST,我想知道我是否可以告诉jaxb将字符串字段"as-it-is"插入到传出的xml中.当然我会在返回之前将其解包,但我想保存这一步.
@XmlRootElement(name="unnestedResponse")
public class Response{
@Insert annotation here ;-)
private String alreadyXml;
private int otherDate; ...
}
是否有可能告诉JAXB只使用String而不是转义？我希望客户端不必解析我的响应,然后解析此字段.
问候,m
我正在研究这些示例，但我根本无法像给定的 cli 示例中那样监听表格。
我的 cli 参数
java -Djava.library.path=./DynamoDBLocal_lib -jar DynamoDBLocal.jar -inMemory
aws dynamodb list-tables --endpoint-url http://localhost:8000
然后它总是要求我提供一个区域并将我指向“aws configure”。当我在凭据和本地区域中输入任何内容时，我得到：
Unable to locate credentials. You can configure credentials by running "aws configure".
我究竟做错了什么？我只是想在使用云本身之前在本地玩一下以更熟悉 cli 界面。让我烦恼，但我无法让它工作。
感谢您的任何提示！
我的实体定义如下:
public class Entity implements Serializeable {
@ManyToMany(mappedBy="entities")
private List<OtherEntity> otherEntities;
}
如何在HQL中选择具有多个OtherEntity的所有实体？
我想使用Criteria API通过从搜索值中获取输入来选择实体.文档可以包含更多收件人.收件人有许多子类
@Entity
public class Document implements Serializable {
@OneToMany(mappedBy="document")
private List<Recipient> recipients = new ArrayList<Recipient>();
@Entity
public class RecipientAccount extends Recipient {
String name;
如何选择具有特定名称的ReciepientAccount的所有文档？我需要搜索所有子类并用OR连接它们.有优雅的方式吗？
问候
我知道hibernate是懒惰的默认提取策略,但有一些事情我不清楚,所以我希望你能解释一下.我想要做的是将标记为标记为起始图块的图块.
查询:
@NamedQuery(name = "Tile.findStartTileByGame",
query = "SELECT t FROM Tile t WHERE t.game = :game " +
"and t.startTile = true and t.blockWalkable = false")
瓦:
public class Tile{
@OneToOne(mappedBy="tile")
private GameCharacter character;
@OneToOne(mappedBy="tile")
private GameObject gameObject;
游戏:
@OneToMany(mappedBy="game")
private List<Tile> tiles;
当我运行我的查询并且从不使用该对象时,hibernate仍然加入了我的角色和游戏对象.所以我有3个查询.我知道我可以通过fetch join来解决这个问题,但我的问题是为什么hibernate会同时获取两个引用？即使我使用fetch = FetchType.LAZY对它们进行注释,也会查询它.
我的DAO:
public static Tile getFreeStartTile(EntityManager em, Game game) {
TypedQuery<Tile> query = em.createNamedQuery("Tile.findStartTileByGame", Tile.class);
query.setParameter("game", game);
List<Tile> result = query.getResultList();
...
在我解决这个问题之前,我想了解它为什么会发生.在此先感谢m
我目前正在编写一个有趣的游戏，我注意到我仍然回到“旧”的循环方式。谁能帮我看看这个方法在使用 lambda 时会是什么样子？
public GameObject findClosestEnemy(Game game, GameObject actor) {
Double minDistance = null;
GameObject closestEnemy = null;
for (GameObject o : game.getObjects()) {
if (isNoEnemy(actor, o)) {
continue;
}
double distance = actor.calculateMinEuclideanDistance(o);
if (minDistance == null || distance < minDistance) {
minDistance = distance;
closestEnemy = o;
}
}
return closestEnemy;
}