小编Cpc*_* Cp的帖子

reverse'::[a] -> [a]
reverse' xs=foldl (\acc x -> x:acc) [] xs
example?
reverse' [1,2,3,4,5]
output:[5,4,3,2,1]

如果我改变acc了[]

reverse' xs=foldl (\acc x -> x:[]) [] xs

它输出

[5]

为什么？