我收到DOMException:无法加载,因为在video.play()中找不到支持的源 ; 线.我只是在添加了video.setAttribute('crossorigin','anonymous')之后才遇到这个问题; 我正在开发移动应用程序,所以对于交叉起源我需要添加这一行.更新chrome 50版本后,我在此之前遇到此问题,它可以正常工作.
<!DOCTYPE html>
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>
</head>
<body>
<script>
var video = document.createElement( 'video' );
video.id = 'video';
video.type = ' video/mp4; codecs="theora, vorbis" ';
video.src = "http://abcde.com/img/videos/what_is_design_thinking.mp4";
video.volume = .1;
video.setAttribute('crossorigin', 'anonymous');
video.load(); // must call after setting/changing source
$('body').html(video);
video.play();
var canvas = document.createElement('canvas');
var ctx = canvas.getContext('2d');
$('body').append(canvas);
video.addEventListener('play', function() {
var $this = this; //cache
(function loop() {
if (!$this.paused && !$this.ended) {
ctx.drawImage($this, 0, 0);
setTimeout(loop, 1000 …我怎么能用css找到最后一个子元素,这是我的代码.
<div class="leftelement"></div>
<div class="rightelement"></div>
<div class="leftelement"></div>
<div class="rightelement"></div>
<div class="leftelement"></div> <!-- this element -->
<div class="rightelement"></div>
我尝试了下面的方法,它不适合我.任何人都可以帮助我.我不想使用nth-child,因为有时候元素的数量会增加
.leftelement:last-of-type并.leftelement:last-child没有工作
我最近开始研究three.js,现在我正面临着文本几何问题.我使用three.js版本75,我使用了js/helvetiker_bold.typeface.js字体.
var geometry = new THREE.TextGeometry( this.txt, {
size: this.textSize,
height: this.textHeight,
curveSegments: 3,
font: this.textFont,
weight: "bold",
style: "normal",
bevelEnabled: false
});
由于以下问题,测试无法渲染
1未捕获的ReferenceError:未定义_typeface_js
2.three.min.js:889 THREE.TextGeometry:font参数不是THREE的实例.Font
任何人都可以帮助我.
是否可以使用jQuery/Javascript根据时间(2016-12-07T13:00:00)重新排列以下JSON格式.
[
{
"id":1,
"start":"2016-12-07T13:00:00",
"subject":"test1",
},
{
"id":2,
"start":"2016-12-07T09:00:00",
"subject":"test2",
},
{
"id":3,
"start":"2016-12-07T10:00:00",
"subject":"test3",
},
{
"id":4,
"start":"2016-12-07T07:00:00",
"subject":"test4",
},
{
"id":5,
"start":"2016-12-07T14:00:00",
"subject":"test5",
}
]