我有一个es6类实例,我需要获取它的所有属性(以及继承的属性).有没有办法在不遍历原型链的情况下做到这一点？
class A {
get a() {
return 123;
}
}
class B extends A {
get b() {
return 456;
}
}
const b = new B();
for (let prop in b) {
console.log(prop); //nothing
}
console.log(Object.keys(b)); //empty array
console.log(Object.getOwnPropertyNames(b)); //empty array
console.log(Reflect.ownKeys(b)); //empty array
console.log(Object.keys(Object.getPrototypeOf(b))); //empty array
console.log(Object.getOwnPropertyNames(Object.getPrototypeOf(b))); //["contructor", "b"] -- without "a"
console.log(Reflect.ownKeys(Object.getPrototypeOf(b))); //["contructor", "b"] -- without "a"