表 who
wid--name-------father---mother
1----Daisy------David----Liza
2----Jenny------Joe------Judy
3----Meggy------Mike-----Manuela
4----Sarah------Joe------Judy
5----Chelsea----Bill-----Hillary
6----Cindy------David----Liza
7----Kelly------Joe------Judy
表 ages
aid---whoid---age
1-----1--------0
2-----2--------0
3-----3-------14
4-----4-------30
5-----5-------22
6-----6-------17
7-----1-------18
我希望该列表成为结果:
id---name------age
1----Meggy-----14
2----Cindy-----17
3----Daisy-----18 (Selected data that bigger than 0)
4----Chelsea---22
5----Sarah-----30
6----Jenny-----30 (Her age is 0 on ages table and Sarah's age with same father and mother)
7----Kelly-----30 (No data on ages table and Sarah's age with same father and mother)
我试过那个查询:
SELECT
*,
(CASE age
WHEN '0' THEN (
SELECT age
FROM ages a
LEFT JOIN who …