我已经使页面的主体高200%,以便它适合屏幕两次.使用javascript我滚动时会一直滚动到顶部或底部.为此,我需要在任何浏览器或屏幕大小上找到页面的最低滚动点,以便在它到达时停止.
请不要JQuery.
谢谢.
我的代码:(它仍然被放在一起所以需要一些工作)
function getScrollXY() {
var x = 0, y = 0;
if( typeof( window.pageYOffset ) == 'number' ) {
// Netscape
x = window.pageXOffset;
y = window.pageYOffset;
} else if( document.body && ( document.body.scrollLeft || document.body.scrollTop ) ) {
// DOM
x = document.body.scrollLeft;
y = document.body.scrollTop;
} else if( document.documentElement && ( document.documentElement.scrollLeft || document.documentElement.scrollTop ) ) {
// IE6 standards compliant mode
x = document.documentElement.scrollLeft;
y = document.documentElement.scrollTop;
}
return [x, y];
}
function scrollup() …我一直收到这个错误
box2.c: In function 'printchars':
box2.c:26:4: warning: passing argument 1 of 'printf' makes pointer from integer without a
cast [enabled by default]
/usr/include/stdio.h:363:12: note: expected 'const char * __restrict__' but argument is
of type 'char' box2.c:26:4: warning: format not a string literal and no format arguments [-Wformat-security]
box2.c:39:8: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [enabled by default]
/usr/include/stdio.h:363:12: note: expected 'const char * __restrict__' but argument is of type 'char'
box2.c:39:8: warning: format …我正在尝试交换循环内的元素。
fn foo(nums: &mut Vec<i32>) {
let mut i: usize = 0;
for (j, n) in nums.iter_mut().enumerate() {
if n != &0 {
// swap nums[i] and nums[j];
i = i + 1;
}
}
}
但我不断收到相同的错误（同时不能多次借用可变 nums）。我究竟做错了什么？