我试图在Windows 7中安装groovy.我从groovy网站下载了存档.解压缩它.添加GROOVY_HOME环境路径.将bin路径添加到环境中.之后我重新启动了Windows.但是当我尝试从cmd运行groovy时,我得到错误:
错误:无法找到或加载主类org.codehaus.groovy.tools.GroovyStarter
我试图从jQuery的.ajax()函数调用一个servlet.
目前我不认为我甚至不会调用servlet或将paramaters传递给它,但是很多Google搜索似乎没有帮助.有任何想法吗？
这是我的HTML:
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript">
function login(){
$("#loading").hide();
var email = document.nameForm.email.value;
$.ajax({
type: "GET",
url: "ProcessForm",
data: "email="+email,
success: function(result){
alert(result);
}
});
}
</script>
<title>My AJAX</title>
</head>
<body>
<p>This time it's gonna work</p>
<form name="nameForm" id="nameForm" method="post" action="javascript:login()">
电邮加载
</body>
</html>
还有我的web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>ajaxtry</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>ProcessForm</servlet-name>
<servlet-class>com.ajaxtry.web.ProcesFormServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>ProcessForm</servlet-name>
<url-pattern>/ProcessForm</url-pattern> …我正在开发Eclipse RCP应用程序,最近我开始在其中使用Groovy.所以99%的代码仍然是Java.
我读到可以使用Groovy覆盖并向Java类添加方法,我可以通过向java.lang.String添加一个方法来测试它.
但这仅在我在Groovy类中使用字符串时才有效.重写的方法不被视为在Java类中被重写.
这是一些代码:
/*
* This is a Java class
*/
public class CTabItem {
...
private API
...
public void setControl(Control control){
private API
}
}
/*
* This is also a Java class
*/
public class Control {
...
private API
...
}
/*
* This is also a Java class
*/
public class OtherClass {
...
private API
...
private void someMethodIDontKnow(){
Control control = new Control();
CTabItem tab = new CTabItem();
tab.setControl(control);
}
} …我正在使用Ready API 1.4.0,我尝试使用这个groovy代码连接到postgresql.
import groovy.sql.Sql
import java.sql.Driver
def driver = Class.forName('org.postgresql.Driver').newInstance() as Driver
def props = new Properties()
props.setProperty("DB_user", "user")
props.setProperty("DB_password", "user")
def conn = driver.connect("jdbc:postgresql://localhost:54320/database_name", props)
def sql = new Sql(conn)
try {
sql.eachRow("select * from user") {
log.debug(it)
}
} finally {
sql.close()
conn.close()
}
然后我收到了这个错误:
java.lang.ClassNotFoundException:org.postgresql.Driver at line:4
我在bin/ext postgresql-9.4-1205.jdbc42.jar中添加了这个jar lib
有什么帮助吗？谢谢.
我有一个叫做的课Test,我有以下代码
def test = new Test()
test.method1(args)
test.method2(args)
等等.我希望可以做到这样的事情,我可以test在闭包中传递对象的所有方法调用并使它们工作.喜欢
test {
method1(args)
method2(args)
}
是否可以在groovy中这样做？
在执行Java到Groovy代码迁移的初始阶段时,我遇到了一个问题,即Groovy版本从Future返回null,而Java返回正确的整数(123).
J1.java和G1.groovy之间唯一的变化是类名和lambda到闭包转换.
//文件:J1.java
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Future;
public class J1 {
public static void main (String... args) throws Exception {
ExecutorService executor = Executors.newFixedThreadPool (1);
Future<Integer> future = executor.submit (() -> 123);
System.out.println ("Result: " + future.get ());
executor.shutdown ();
}
}
//文件:G1.groovy
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Future;
public class G1 {
public static void main (String... args) throws Exception {
ExecutorService executor = Executors.newFixedThreadPool (1);
Future<Integer> future = executor.submit ({ -> 123 });
System.out.println ("Result: " …groovy ×5
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