小编Ton*_*min的帖子

由于一个奇怪的请求,我试图拒绝,但它没有工作,我不得不覆盖navigationBar的后退按钮.

我已经制作了一个自定义的UINavigationController子类并且破解了该 - (BOOL)navigationBar:(UINavigationBar *)navigationBar shouldPopItem:(UINavigationItem *)item方法.

这是我的代码:

@interface CustomUINavigationController ()

@end

@implementation CustomUINavigationController


#pragma mark - UINavigationBar delegate methods

- (BOOL)navigationBar:(UINavigationBar *)navigationBar shouldPopItem:(UINavigationItem *)item {

    if ([[self.viewControllers lastObject] isKindOfClass:[ViewController1 class]]) {
        ViewController1 *vc1 = (ViewController1 *)[self.viewControllers lastObject];
        [vc1 handleBackAction];
        if (vc1.canPopVC == YES) { 
            [self popViewControllerAnimated:YES];
            return YES;
        } else {
            return NO;
        }
    }

    [self popViewControllerAnimated:YES];
    return YES;
}

@end

一切正常,除非我以编程方式弹出viewController.每次我想在弹出后执行推送时,应用程序都会崩溃.转向NSZombie on,显示当以编程方式弹出viewController时,其父viewController被释放.此时,制作自定义backButton不是一个选项,因为它将丢失原生iOS 7滑动到popViewController功能.

崩溃日志:

*** -[ContactsDetailViewController performSelector:withObject:withObject:]: message sent to deallocated instance 0x1806b790