小编kyl*_*las的帖子

我正在尝试在我的Ubuntu 14.04.3 LTS上安装NetBeans 8.1.当我尝试创建一个新项目时,它显示一个错误,说"并非所有请求的模块都可以启用".我尝试从插件中激活它,但无济于事.

为什么会发生这种情况,我该怎么做才能解决它？

我试图运行我从某人那里得到的一个新的 React Native (Android) 项目。当我运行 yarn install 时，出现以下错误。我怎样才能解决这个问题 ？我是本机反应的新手。

patch-package: Applying patches...

**ERROR** Failed to apply patch for package react-native-confirmation-code-input

  This error was caused because Git cannot apply the following patch file:

    patches/react-native-confirmation-code-input+1.0.4.patch

  This is usually caused by inconsistent whitespace in the patch file.  

  public void signInWithLinkedIn(View view){
        LISessionManager.getInstance(getApplicationContext()).init(this, buildScope(), new AuthListener() {
            @Override
            public void onAuthSuccess() {

                Toast.makeText(getApplicationContext(), "success" + LISessionManager.getInstance(getApplicationContext()).getSession().getAccessToken().getValue(), Toast.LENGTH_LONG).show();
                Log.d("SESSION", Boolean.toString(LISessionManager.getInstance(getApplicationContext()).getSession().isValid()));
                //fetchBasicProfileData();
            }

            @Override
            public void onAuthError(LIAuthError error) {

                Toast.makeText(getApplicationContext(), "failed " + error.toString(),
                        Toast.LENGTH_LONG).show();
            }
        }, true);

        // After complete authentication start new HomePage Activity
    }

已onAuthSuccess执行的代码块但getSession返回null,最重要的是访问令牌为null,使我无法调用其他linkedin API.这种情况最近才发生.我做得对吗？

更新: - 还有一件事情通常发生在几个特定的​​LinkedIn ID并且与其余的id一起正常工作.

我的XML布局如下:

<android.support.design.widget.CoordinatorLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:app="http://schemas.android.com/apk/res-auto"
    android:id="@+id/coordinatorLayout"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent">

    <!-- AppBar Layout   -->
    <android.support.design.widget.AppBarLayout
        android:id="@+id/appBarLayout"
        android:layout_width="fill_parent"
        android:layout_height="wrap_content"
        android:theme="@style/ThemeOverlay.AppCompat.Dark.ActionBar">

        <android.support.v7.widget.Toolbar
            android:id="@+id/toolbar"
            android:layout_width="fill_parent"
            android:layout_height="?attr/actionBarSize"
            android:background="?attr/colorPrimary"
            app:layout_scrollFlags="scroll|enterAlways"
            app:popupTheme="@style/ThemeOverlay.AppCompat.Light" >
            <Button
                android:id="@+id/filter_location"
                android:layout_width="wrap_content"
                android:layout_height="wrap_content"
                style="?android:attr/borderlessButtonStyle"
                android:drawableRight="@drawable/ic_filter_list_white_24dp"
                android:layout_gravity="right"
                />
        </android.support.v7.widget.Toolbar>
        <!-- Tab Layout for creating tabs -->
        <android.support.design.widget.TabLayout
            android:id="@+id/tabLayout"
            android:layout_width="fill_parent"
            android:layout_height="wrap_content" />
    </android.support.design.widget.AppBarLayout>
    <!-- Helps handing the Fragments for each Tab -->
    <android.support.v4.view.ViewPager
        android:id="@+id/viewPager"
        android:layout_width="fill_parent"
        android:layout_height="fill_parent"
        app:layout_behavior="@string/appbar_scrolling_view_behavior" />

    <android.support.design.widget.FloatingActionButton
        android:id="@+id/float_search"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_gravity="bottom|end"
        android:layout_marginBottom="70dp"
        android:src="@android:drawable/ic_menu_search" />

    <android.support.design.widget.BottomNavigationView
        android:id="@+id/bottom_navigation"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:layout_gravity="bottom"
        android:background="@color/colorPrimary"
        app:itemBackground="@color/colorPrimary"
        app:itemIconTint="@color/windowBackground"
        app:itemTextColor="@color/windowBackground"
        app:menu="@menu/bottom_navigation_main" /> …

<v-btn-toggle v-model="toggle_one">
   <v-btn flat>
      USD50
   </v-btn>
   <v-btn flat>
      USD100
   </v-btn>
   <v-btn flat>
      USD1000
   </v-btn>
   <v-btn flat>
      USD10000
   </v-btn>

用户只能选择一个选项。如何获取所选按钮的值？

Login.vue 是我设置 sessionStorage 的地方

sessionStorage.setItem('accessToken', response.data.response.accessToken)

Logout.vue 是我要删除 sessionStorage 的地方

sessionStorage.removeItem('accessToken')

但是，注销并重定向到 Login.vue 后，accessToken 值仍然在 sessionStorage 中。我做错了吗？

HTML

<v-select
  v-model="selectedBank"
  :items="items"
  item-text="bankName"
  label="Select a bank"
  persistent-hint
  return-object
  single-line
>
</v-select>

<v-btn 
  round 
  block 
  color="blue darken-3" 
  dark 
  large 
  @click="directToBank(items.bankName)"
>
  CONTINUE
</v-btn>

JS

async directToBank(bankID) {
  console.log("Came into directtobank", this.selectedBank.bankName)
}

如何v-select在单击按钮时获得选定的值？. .

    public void signInWithLinkedIn(View view) {
        //First check if user is already authenticated or not and session is valid or not
        if (!LISessionManager.getInstance(this).getSession().isValid()) {
            //if not valid then start authentication
            LISessionManager.getInstance(getApplicationContext()).init(LinkedInActivity.this, buildScope()//pass the build scope here
                    , new AuthListener() {
                        @Override
                        public void onAuthSuccess() {
                            // Authentication was successful. You can now do
                            // other calls with the SDK.
                            Toast.makeText(LinkedInActivity.this, "Successfully authenticated with LinkedIn.", Toast.LENGTH_SHORT).show();

                            //on successful authentication fetch basic profile data of user
                            //LISessionManager.getInstance(getApplicationContext()).clearSession();
                            fetchBasicProfileData();
                        }

                        @Override
                        public void onAuthError(LIAuthError …

我试图从 Eclipse 运行 Elastic MapReduce，但无法这样做。

我的代码如下：

public class RunEMR {

    /**
     * @param args
     */
    public static void main(String[] args) {
        // TODO Auto-generated method stub
         AWSCredentials credentials = new BasicAWSCredentials("xxxx","xxxx");
            AmazonElasticMapReduceClient emr = new AmazonElasticMapReduceClient(credentials);

            StepFactory stepFactory = new StepFactory();

            StepConfig enableDebugging = new StepConfig()
                .withName("Enable Debugging")
                .withActionOnFailure("TERMINATE_JOB_FLOW")
                .withHadoopJarStep(stepFactory.newEnableDebuggingStep());

            StepConfig installHive = new StepConfig()
                .withName("Install Hive")
                .withActionOnFailure("TERMINATE_JOB_FLOW")
                .withHadoopJarStep(stepFactory.newInstallHiveStep());

            StepConfig hiveScript = new StepConfig().withName("Hive Script")
                .withActionOnFailure("TERMINATE_JOB_FLOW")
                .withHadoopJarStep(stepFactory.newRunHiveScriptStep("s3://mywordcountbuckett/binary/WordCount.jar"));

            RunJobFlowRequest request = new RunJobFlowRequest()
                .withName("Hive Interactive")
                .withSteps(enableDebugging, installHive)
                .withLogUri("s3://mywordcountbuckett/")
                .withInstances(new JobFlowInstancesConfig()
                    .withEc2KeyName("xxxx") …

我从 Sendgrid 网站设计了一个模板。我们就这样称呼它吧sendgrid.html

Nodejs我正在尝试发送带有设计的电子邮件sendgrid.html。下面是我的 Nodejs 代码：

function sendVoucherCodeEmail (emailAddress, voucherCode){
    sgMail.setApiKey(process.env.SENDGRID_API_KEY);
    const msg = {
        to: emailAddress,
        from: 'example@example.com',
        subject: 'YourCode',
        text: ''
    };
}

我想传递emailAddress和voucherCode到 html 内容并将其作为电子邮件发送给用户。我该怎么做 ？先感谢您。