小编Ara*_*asu的帖子

我有一个读取文件并返回字符串的方法,但我想返回一个读者.我想将字符串转换为读者,或者我想读取文件并返回阅读器.我怎样才能做到这一点？

我创建了一个播放应用程序.当我运行应用程序时,我在dev和prod中都会收到此错误

07:59:58,445 INFO  ~ Precompiling ...
08:00:08,884 ERROR ~ Unable to set localhost. This prevents creation of a GUID. Cause was: sys3: sys3: Name or service not known
java.net.UnknownHostException: sys3: sys3: Name or service not known
    at java.net.InetAddress.getLocalHost(InetAddress.java:1438)
    at net.sf.ehcache.Cache.<clinit>(Cache.java:155)
    at net.sf.ehcache.config.ConfigurationHelper.createCache(ConfigurationHelper.java:298)
    at net.sf.ehcache.config.ConfigurationHelper.createDefaultCache(ConfigurationHelper.java:214)
    at net.sf.ehcache.CacheManager.configure(CacheManager.java:552)
    at net.sf.ehcache.CacheManager.init(CacheManager.java:323)
    at net.sf.ehcache.CacheManager.<init>(CacheManager.java:279)
    at net.sf.ehcache.CacheManager.create(CacheManager.java:641)
    at play.cache.EhCacheImpl.<init>(EhCacheImpl.java:31)
    at play.cache.EhCacheImpl.newInstance(EhCacheImpl.java:41)
    at play.cache.Cache.init(Cache.java:241)
    at play.Play.start(Play.java:511)
    at play.Play.init(Play.java:300)
    at play.server.Server.main(Server.java:158)
Caused by: java.net.UnknownHostException: sys3: Name or service not known
    at java.net.Inet6AddressImpl.lookupAllHostAddr(Native Method)
    at java.net.InetAddress$1.lookupAllHostAddr(InetAddress.java:866)
    at java.net.InetAddress.getAddressesFromNameService(InetAddress.java:1258) …

我正在检查互联网是否可用

URL url = new URL("http://www.google.co.in/");
            final HttpURLConnection conn = (HttpURLConnection) url.openConnection();

            // set connect timeout.
            conn.setConnectTimeout(1000000);

            // set read timeout.
            conn.setReadTimeout(1000000);

            conn.setRequestMethod("POST");

            conn.setRequestProperty("Content-Type","text/xml");

            conn.setDoOutput(true);

            conn.connect();

            Integer code = conn.getResponseCode();
            final String contentType = conn.getContentType();

在运行此代码时,我得到了例外

URLjava.io.IOException: Server returned HTTP response code: 411

可能是什么错误.

我正在使用Play框架.我有一个JSONObject,其结构如下(在打印的控制台中)

{
    "rows_map":{
        "220":["mahesh",
            "outfit:bmtech,app:salesreport,uuname,ffname,llname",
            "Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.0.5",
            null
        ],
"221":["mahesh",
            "outfit:bmtech,app:salesreport,uuname,ffname,llname",
            "Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.0.5",
            null
        ],
"222":["mahesh",
            "outfit:bmtech,app:salesreport,uuname,ffname,llname",
            "Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.0.5",
            null
        ],
"223":["mahesh",
            "outfit:bmtech,app:salesreport,uuname,ffname,llname",
            "Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.0.5",
            null
        ]
},
    "columns_map":["Sender",
        "Message Received",
        "Device",
        "Time"
    ]
}

我想将此JSONObject写入文件.这是代码

String path = "/var/www/html/Prj/public/CacheLayer/Incoming_Cache/CacheFileMgr.cache";

            ObjectOutputStream outputStream = null;
        try{
            outputStream = new ObjectOutputStream(new FileOutputStream(path));
            System.out.println("Start Writings");
                outputStream.writeObject(object);
                outputStream.flush();
                    outputStream.close();
          }catch (Exception e){
          System.err.println("Error: " …

我是Play的新手,也是休眠和JPA的新手.我正在使用MySql DB和JPA

import javax.persistence.Entity;
import javax.persistence.EntityManager;
import javax.persistence.EntityManagerFactory;
import javax.persistence.EntityTransaction;
import javax.persistence.Persistence;
import javax.persistence.Query;

import play.db.jpa.JPA;
import play.mvc.Controller;
import play.db.jpa.*;

我有这个查询

List languages = FormLanguages.findAll();
render(languages);

哪个运行正常,但我想基于id选择,像这样

"select*from FormLanguages,其中id> 10"

当我这样使用

Query query = JPA.em().createQuery("select * from FormLanguages");
List<FormLanguages> articles = query.getResultList();
render(articles);

这给了我IllegalArgumentException错误

当这样使用时

List queryList = FormLanguages.em().createQuery("select * from FormLanguages").getResultList();
render(queryList);

给出同样的错误请帮我看看如何编写Query

还建议我一些网站

我有JQuery Datatable,我想删除行,当点击删除链接时.它适用于前10行,即第一页.当我从分页移动到另一个.它不起作用.这是我的代码:

$("#example tbody td.delete").click(function(event) {
                var row = $(this).closest("tr").get(0);
                oTable.fnDeleteRow( row );
    });

行的所有最后一行都有"删除"类.

我该怎么做才能为所有页面或所有记录工作？

我正在使用jQuery Mobile.其实我想在弹出窗口中打开一个externl链接.我试过这个.

<a href="#" id="dialoglink"  data-rel="dialog">Open Dialog</a>
<script>
$(document).delegate('#dialoglink', 'click', function() {
    $(this).simpledialog({
        'mode' : 'blank',
        'prompt': false,
        'forceInput': false,
        'useModal':true,
        'fullHTML' : 
            'http://www.google.com/'
    })
});
</script>

它打开一个弹出窗口,内容是http://www.google.com/.但我其实想加载网址.即谷歌索引页面.

我的示例json文件内容

{
"FlightLog":{
    "FlightLog.crewMembers":[

    ],
    "destinationStationCode":"JPN",
    "FlightLog.destinationStationCode":"IND",
    "FlightLog.originStationCode":"IND",
    "FlightLog._lockVersion":"0",
    "FlightLog.flightNum":"123"
}
}

我想获得FlightLog.FlightLog.originStationCode的价值.

例如:当我声明如下字段名称时,我得到的值是"JPN"

<field name="FlightLog.destinationStationCode" class="java.lang.String">
    <fieldDescription><![CDATA[FlightLog.destinationStationCode]]></fieldDescription>
</field>

如果我声明如下字段,

<field name="destinationStationCode" class="java.lang.String">
    <fieldDescription><![CDATA[FlightLog.FlightLog.destinationStationCode]]></fieldDescription>
</field>

我没有得到上述代码的任何价值.

我试过用

<field name="destinationStationCode" class="java.lang.String">
    <fieldDescription><![CDATA[FlightLog[FlightLog.destinationStationCode]]]></fieldDescription>
</field>
<field name="destinationStationCode2" class="java.lang.String">
    <fieldDescription><![CDATA[FlightLog.FlightLog\\.destinationStationCode]]></fieldDescription>
</field>

我怎样才能做到这一点？

UPDATE

我的jrxml是,

<?xml version="1.0" encoding="UTF-8"?>
<jasperReport xmlns="http://jasperreports.sourceforge.net/jasperreports" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://jasperreports.sourceforge.net/jasperreports http://jasperreports.sourceforge.net/xsd/jasperreport.xsd" name="Test" pageWidth="595" pageHeight="842" columnWidth="555" leftMargin="20" rightMargin="20" topMargin="20" bottomMargin="20" uuid="062e3e2d-b648-49c7-b4a5-1d3c4fbdfc6b">
    <queryString language="json">
        <![CDATA[]]>
    </queryString>
    <field name="FlightLog" class="java.lang.Object">
        <fieldDescription><![CDATA[FlightLog]]></fieldDescription>
    </field>
    <detail>
        <band height="20" splitType="Stretch">
            <textField isStretchWithOverflow="true">
                <reportElement x="0" y="0" width="555" height="20" uuid="dc09b2c4-31b1-4458-8097-2e912e80b3a2"/>
                <textFieldExpression><![CDATA[$F{FlightLog}.get("FlightLog.destinationStationCode")]]></textFieldExpression>
            </textField> …

我正在使用magento 1.5.0.1.在我的主页中,我想显示类别,我创建了3个类别,并在管理员中给出了是活动选项.我想在我的主页上显示带有链接的这些类别.在主页我有这些代码

<reference name="content">
<block type="catalog/product_new" name="home.catalog.product.new" alias="product_new" template="catalog/product/new.phtml" after="product_list"><action method="addPriceBlockType"><type>bundle</type><block>bundle/catalog_product_price</block><template>bundle/catalog/product/price.phtml</template></action></block>
</reference>

如何更改此选项以查看类别.我是magento的新手.请帮帮我......

在添加类别时,我已将Include in Navigation Menu设置为yes.

我正在使用Magento ver.1.5.0.1.在主页我用左栏2列.我想一个接一个地展示最新,最高评价和最好的产品.请帮我怎么做.我是magento的新手,请帮助我......